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3 years ago

8

If a 40 foot telephone pole casts a 34 foot shadow at the same time that a nearby tree casts a 28 foot shadow, how tall is the t

ree?

1 answer:

kodGreya [7K]3 years ago

4 0

Answer:

22

Step-by-step explanation:

40 - 34 = 6

28 - 6 = 22

I'm not sure if there's any dividing or multiplying involved in this but I did my best..

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Sally is making a

kogti [31]

Answer:

784

Step-by-step explanation:

you take the 49 and times is by 16

there are 4 sides

7 0

3 years ago

(2a divided by 7) - (a-4)

Shkiper50 [21]

Answer:

a=28/5 or 5.6

Step-by-step explanation:

2a/7=a-4

Multiple both sides of the equation by 7

2a=7a-28

Subtract 7a from both side

2a-7a=-28

Like Term

-5a=-26

Divide -5 from both side

a= 5.6

6 0

2 years ago

Can someone please explain how to do this!!!

DedPeter [7]

Hi there!

So we are given that:-

tan theta = 7/24 and is on the third Quadrant.

In the third Quadrant or Quadrant III, sine and cosine both are negative, which makes tangent positive.

Since we want to find the value of cos theta. cos must be less than 0 or in negative.

To find cos theta, we can either use the trigonometric identity or Pythagorean Theorem. Here, I will demonstrate two ways to find cos.

<u>U</u><u>s</u><u>i</u><u>n</u><u>g</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>I</u><u>d</u><u>e</u><u>n</u><u>t</u><u>i</u><u>t</u><u>y</u>

$\large \displaystyle{ {tan}^{2} \theta + 1 = {sec}^{2} \theta}$

Substitute tan theta = 7/24 in.

$\large \displaystyle{ {( \frac{7}{24}) }^{2} + 1 = {sec}^{2} \theta }$

Evaluate.

$\large \displaystyle{ \frac{49}{576} + 1 = {sec}^{2} \theta} \\ \large \displaystyle{ \frac{625}{576} = {sec}^{2} \theta}$

Reminder -:

$\large \displaystyle{ sec \theta = \frac{1}{cos \theta} }$

Hence,

$\large \displaystyle{ \frac{576}{625} = {cos}^{2} \theta} \\ \large \displaystyle{ \sqrt{ \frac{576}{625} } = cos \theta} \\ \large \displaystyle{ \frac{24}{25} = cos \theta}$

Because in QIII, cos<0. Hence,

$\large \displaystyle \boxed{ \blue{cos \theta = - \frac{24}{25} }}$

<u>U</u><u>s</u><u>i</u><u>n</u><u>g</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>P</u><u>y</u><u>t</u><u>h</u><u>a</u><u>g</u><u>o</u><u>r</u><u>e</u><u>a</u><u>n</u><u> </u><u>T</u><u>h</u><u>e</u><u>o</u><u>r</u><u>e</u><u>m</u>

$\large \displaystyle{ {a}^{2} + {b}^{2} = {c}^{2} }$

Define c as our hypotenuse while a or b can be adjacent or opposite.

Because tan theta = opposite/adjacent. Therefore:-

$\large \displaystyle{ {7}^{2} + {24}^{2} = {c}^{2} } \\ \large \displaystyle{49 + 576 = {c}^{2} } \\ \large \displaystyle{625 = {c}^{2} } \\ \large \displaystyle{25 = c}$

Thus, the hypotenuse side is 25. Using the cosine ratio:-

$\large \displaystyle{cos \theta = \frac{adjacent}{hypotenuse}}$

Therefore:-

$\large \displaystyle{cos \theta = \frac{24}{25} }$

Because cos<0 in Q3.

$\large \displaystyle \boxed{ \red{cos \theta = - \frac{24}{25} }}$

Hence, the value of cos theta is -24/25.

Let me know if you have any questions!

8 0

2 years ago

I’m circle v, r=14ft

Savatey [412]

A = pi(r)^2
a= pi (14)^2
a=196pi

6 0

3 years ago

Let f(x)=7x−4, g(x)=x2+4, and h(x)= x+4 7. <br> Evaluate the expression (f◦g◦h)(3).

umka2103 [35]

Step-by-step explanation:

(x/z)=3 (7/5)= x'2

tis is the right answer

plz mark me branlists

7 0

2 years ago