Ask question

Ask question

All categories

3 years ago

15

£140 is divided between Angad, Nick & June so that Angad gets twice as much as Nick, and Nick gets three times as much as Ju

ne. How much does Angad get?

1 answer:

Vladimir79 [104]3 years ago

3 0

Answer:

£84

Step-by-step explanation:

The given ratios are ...

A : N = 2 : 1

N : J = 3 : 1

Putting these together, we have ...

A : N : J = 6 : 3 : 1

There are a total of 6+3+1 = 10 ratio units, so each is worth £140/10 = £14.

Angad's share is 6×£14 = £84.

_____

<em>Check</em>

Nick gets £42, and June gets £14. Together, they share £84 +42 +14 = £140.

You might be interested in

Find the slope of the horizontal line that passes through the points (5,3) and (8,3)

elena-14-01-66 [18.8K]

The slope is 0 the equation of the line is y=3

6 0

3 years ago

At the end of the year, a library reported 32 books lost or stolen, and 24 books were sent out for repair. If the library origin

Anettt [7]

We subtract 32 and 24 from 1219 and we get the answer. 1219-32-24=1163. 1,163 books were left.

5 0

3 years ago

What are all of the real roots of the following polynomial? f(x) x^4-24x^2-25

Greeley [361]

<u>Answer:</u>

x = ±5

<u>Step-by-step explanation:</u>

We are given the following polynomial function and we are to find all of its real roots:

$x^4-24x^2-25$

Let $y=x^2$ so we can now write it as:

$y^2-24y-25$

Factorizing it to get:

$(y^2+y)+(-25y-25)$

$y\left(y+1\right)-25\left(y+1\right)$

$\left ( y + 1 \right ) \left ( y - 2 5 \right)$

Substitute back $y=x^2$ to get:

$\left ( x^2 + 1 \right ) \left ( x^2 - 25 \right )$

$\left ( x^2 + 1 \right ) \left ( x + 5 \right ) \left ( x - 5 \right )$

The quadratic factor has only complex roots. Therefore, the real roots are x = ±5.

3 0

4 years ago

Read 2 more answers

5^(2x-1)+5^(x+1)=250<br> how do you solve?<br> thank you

zepelin [54]

Answer:

<em>x = 2</em>

Step-by-step explanation:

<u>Exponential Equations</u>

Solve:

$5^{2x-1}+5^{x+1}=250$

Separate each exponential:

$5^{2x}5^{-1}+5^{x}5^{1}=250$

Operating:

$\displaystyle \frac{5^{2x}}{5}+5^{x}5=250$

Multiplying by 5:

$5^{2x}+25\cdot5^x=1250$

Rearranging:

$5^{2x}+25\cdot5^x-1250=0$

Recall that:

$5^{2x}=(5^{x})^2$

$(5^{x})^2+25\cdot5^x-1250=0$

Calling

$y=5^{x}:$

$y^2+25y-1250=0$

Factoring:

$(y-25)(y+50)=0$

There are two possible solutions:

y=25

y=-50

Since

$y=5^{x}$

y cannot be negative, thus:

$5^{x}=25=5^2$

The solution is:

x = 2

8 0

3 years ago

Dave has 15$ to spend on an 8$ book and two birthday cards (cl for his friends. how much can he spend on each card if he buys th

vova2212 [387]

X=15

(X-8)/2

Does that work?

6 0

4 years ago