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3 years ago

What is 269.50 divided by 14?

Mathematics

1 answer:

Ira Lisetskai [31]3 years ago

3 0

Your answer would be 19.25

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Find the percent change.<br> 155 pounds to 130 pounds.

Romashka [77]

Answer:

130 pounds is about 84% of 155

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2 years ago

Solve 73 make sure to also define the limits in the parts a and b

Aleks04 [339]

73.

$f(x)=\frac{3x^4+3x^3-36x^2}{x^4-25x^2+144}$

$\lim_{x\to\infty}f(x)=\lim_{x\to\infty}(\frac{3+\frac{3}{x}-\frac{36}{x^2}}{1-\frac{25}{x^2}+\frac{144}{x^4}})=3$ $\lim_{x\to-\infty}f(x)=\lim_{x\to-\infty}(\frac{3+\frac{3}{x}-\frac{36}{x^2}}{1-\frac{25}{x^2}+\frac{144}{x^4}})=3\cdot\frac{1}{2}=3$

Since we can't divide by zero, we need to find when:

$x^4-2x^2+144=0$

But before, we can factor the numerator and the denominator:

$\begin{gathered} \frac{3x^2(x^2+x-12)}{x^4-25x^2+144}=\frac{3x^2((x+4)(x-3))}{(x-3)(x-3)(x+4)(x+4)} \\ so: \\ \frac{3x^2}{(x+3)(x-4)} \end{gathered}$

Now, we can conclude that the vertical asymptotes are located at:

$\begin{gathered} (x+3)(x-4)=0 \\ so: \\ x=-3 \\ x=4 \end{gathered}$

so, for x = -3:

$\lim_{x\to-3^-}f(x)=\lim_{x\to-3^-}-\frac{162}{x^4-25x^2+144}=-162(-\infty)=\infty$ $\lim_{x\to-3^+}f(x)=\lim_{x\to-3^+}-\frac{162}{x^4-25x^2+144}=-162(\infty)=-\infty$

For x = 4:

$\lim_{x\to4^-}f(x)=\lim_{n\to4^-}\frac{384}{x^4-25x^2+144}=384(-\infty)=-\infty$ $\lim_{x\to4^-}f(x)=\lim_{n\to4^-}\frac{384}{x^4-25x^2+144}=384(-\infty)=-\infty$

4 0

5 months ago

How much is left after 24,815.00 in taxes is deducted from an annual salary of 83,500.00

Debora [2.8K]

$58,685 would be the amount left over.

6 0

2 years ago

What is the area of is circle? <br> (circle is 4cm)<br> Area= ? cm[2]

elena-14-01-66 [18.8K]

Answer:

16 cms if each side is 4. cc

3 0

2 years ago

Please help me thank you I appreciate it

Volgvan

Answer:

68°

Step-by-step explanation:

PRQ = SRQ gives:

3x-8 = 2x+6

x = 6+8 = 14

So PRQ = SRQ = 34

and

PRS = PRQ+SRQ = 68

4 0

2 years ago