Oxidation states number (OSN) show how many electrons gained, lost or shared during chemical reactions.
Here are some rules of oxidation state numbers.
1. OSN of 1A elements in compounds is +1
2. OSN of Oxygen in compounds is -2
3. Sum of OSN of elements equals zero in neutral compounds.
4. OSN of free elements is zero. ex. F2, N2, O2.. all have 0 OSN.
If an element loses electrons during reaction, it is oxidized. That element is called as reducing agent.
If an element gains electrons during reaction, it is reduced. That element is called as oxidizing agent.
In the given reaction, potassium perchlorate decompose into potassium chlorate and oxygen.
a) KClO4.
K (potassium) is 1A element, OSN +1,
Oxygen in the compound has OSN -2.
Let OSN of Cl be x
1+ x+(4*-2)=0 (since compound is neutral)
Solve the equation. X is equal to +7.
b)Potassium perchlorate is the reactant, Potassium chloride and Oxygen are the products.
Reactants -----> Products
c) Check out change of OSN of elements.
in KCl, OSN number of K is +1, Cl is -1. So Cl+7---->Cl-1. It takes 8 electrons. It was reduced.
in KClO4, OSN number of O is -2, in O2 it becomes O. So O-2---->O. It gives electrons. It was oxidized.
Shortly,
LOSS OF ELECTRONS=OXIDIZED
GAIN OF ELECTRONS=REDUCED
Answer:
There are 14 cm in 0.14 m
The number of formula units in 2.50 mol of the compound is 15.1 * 10^23.
The question is unclear whether NaNO2 or NaNO3 is implied. However,in either case, the solution applies equally.
6.02 * 10^23 formula units of the compound are contained in 1 mole
x formula units are contained in 2.5 moles of the compound
x = 6.02 * 10^23 formula units * 2.5 moles/ 1 mole
x = 15.1 * 10^23 formula units of the compound.
Learn more; brainly.com/question/9743981
Explanation:
To get a better understanding of the answer,let's take use of Fajan's rule which says that no bond is neither purely covalent or purely ionic.
For ionic compounds MP and BP are higher than covalent compounds. So in order to find the one with higher MP,it's enough to find the most ionic compound among the given options.
In LiF,LiCl,LiBr and LiI,The cation is same and anion only differs.According to Fajans rule Smaller anion and larger cation favours ionic bonding and vice versa. Since Fluoride is the smallest anion,LiF is the most ionic compound and hence it is the one with highest MP from the options.Hope it helps
E. decomposition
hope this helps!
