Answer:
it helps us with our blood (Little)
Answer: The new concentration of a solution of
is 0.2 M 10.0 mL of a 2.0 M
solution is diluted to 100 mL.
Explanation:
Given:
= 10.0 mL,
= 2.0 M
= 100 mL,
= ?
Formula used to calculate the new concentration is as follows.

Substitute the values into above formula as follows.

Thus, we can conclude that the new concentration of a solution of
is 0.2 M 10.0 mL of a 2.0 M
solution is diluted to 100 mL.
The arrangement of the solutions based on their absorption from highest frequency to lowest frequency :
b.
> c.
> a.NaCl
<h3>What is absorption frequency?</h3>
- The frequency of the molecular vibration that led to the absorption is the same as the absorption frequency of a basic IR absorption band.
- In a way, an emission spectrum is the opposite of an absorption spectrum.
- The discrepancies in the energy levels of each chemical element's orbitals correspond to absorption lines for each chemical element at various particular wavelengths.
- Therefore, it is possible to identify the constituents in a gas or liquid using its absorption spectrum.
- Absorption spectroscopy is most frequently used to measure infrared, atomic, visible, ultraviolet (UV), and x-ray waves.
Learn more about Absorption frequency here:
brainly.com/question/5032775
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Balanced equation:
<span>CaO + 2 HCl --> CaCl2 + H2O </span>
<span>Calculate moles of each reactant: </span>
<span>60.4 g CaO / 56.08 g/mol = 1.08 mol CaO </span>
<span>69.0 g HCl / 36.46 g/mol = 1.89 mol HCl </span>
<span>Identify the limiting reactant: </span>
<span>Moles CaO needed to react with all HCl: </span>
<span>1.89 mol HCl X (1 mol CaO / 2 mol HCl) = 0.946 mol CaO </span>
<span>Because you have more CaO than that available, HCl is the limiting reactant. </span>
<span>Calculate moles and mass CaCl2: </span>
<span>1.89 mol HCl X (1 mol CaCl2 / 2mol HCl) X 111.0 g/mol = 105 g CaCl2</span>