Answer:i dont know the answer
Answer:
mass of Helium = mole of Helium x Molarmass of Helium
Explanation:
Mole of Helium = volume of Helium/ 22.4dm^3/mol
= 7.00 x 10^2/22.4
= 31.25mol
Mass of Helium = mole of Helium x Molarmass of Helium
= 31.25mol x 4g/mol
= 125g
0.116 V is the e value for the oxidation of cytochrome c by the cue redox center in complex iv when the ratio of cyst c (fe3 ) /cyst c (fe2 ) is 20 and the ratio of cue (cu2 )/cue (cu ) is 3.
<h3>
Explain the process of oxidation of cytochrome c.</h3>
When cytochrome c is oxidized by mitochondrial cytochrome oxidase (COX), it attaches to Apaf-1 to produce the apoptozole, which activates pro-caspase-9 and causes cell death. Cyst can be created from cytosolic cytochrome c. In the IMS, oxidized cytochrome c can scavenge superoxide without converting it into H2O2, a process that happens naturally but is accelerated by SOD. The benefit of scavenging superoxide independently of H2O2 synthesis is reducing the possibility of hydroxyl radical generation via the Fenton reaction.
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Answer:
hydrated ferric oxide is ferric hydoxide sol and is positively charged. When aqueous solution of NaCl is added to it,the Cl- ions neutralise the positive charge on the sol particles. In the absence of charge, brown precipitate is formes due to colloids can be coagulation of particles.Nov 11, 2020
Explanation: hope this help
Answer:
6,216.684 kilograms of sodium carbonate must be added to neutralize 
of sulfuric acid solution.
Explanation:
Mass of sulfuric acid solution = 
Percentage mass of sulfuric acid = 95.0%
Mass of sulfuric acid = 
Moles of sulfuric acid = 
According to reaction , 1 mole of sulfuric acid is neutralized by 1 mole of sodium carbonate.
Then 58,647.96 moles of sulfuric acisd will be neutralized by :
of sodium carbonate
Mass of 58,647.96 moles of sodium carbonate :
6,216,683.76 g = 6,216,683.76 × 0.001 kg = 6,216.684 kg
6,216.684 kilograms of sodium carbonate must be added to neutralize of sulfuric acid solution.
