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kow [346]
3 years ago
8

Very easy significant figures question!

Chemistry
1 answer:
Anon25 [30]3 years ago
4 0

As you said, the answer is 150.

But in all the numbers, there's a comma with two zeros, and so you have to put them in your answer : 150,00

They are the significative numbers.

Hope it helps

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For many years chloroform (CHCl3) was used as an inhalation anesthetic in spite of the fact that it is also a toxic substance th
Debora [2.8K]

Hey there!:

Molar mass:

CHCl3 = ( 12.01 * 1 )+ (1.008 * 1 ) + ( 35.45 * 3 ) => 119.37 g/mol

C% =  ( atomic mass C / molar mass CHCl3 ) * 100

For C :

C % =  (12.01 / 119.37 ) * 100

C% = ( 0.1006 * 100 )

C% =  10.06 %

For H :

H% = ( atomic mass H / molar mass CHCl3 ) * 100

H% = ( 1.008 / 119.37 ) * 100

H% = 0.008444 * 100

H% = 0.8444 %

For Cl :

Cl % ( molar mass Cl3 / molar mass CHCl3 ):

Cl% =  ( 3 * 35.45 / 119.37 ) * 100

Cl% =  ( 106.35 / 119.37 ) * 100

Cl% = 0.8909 * 100

Cl% = 89.9%


Hope that helps!

4 0
3 years ago
What is the cation and anion of NaOH
Wewaii [24]

Answer:

naoh is called sodium hydroxide,

Explanation:

hope this helps

6 0
3 years ago
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what is the pH of a solution made by adding 0.30 mol of acetic acid and 0.30 mol of sodium acetate to enough water to make 1.0L
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If x=0 then y=0 sorry dude I wish I could
Help but I’m dumb and I just want points but I’d defiantly recommend to look this up on safari or go into school and seek help
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Chemical bonding is the combining of atoms to form ______________?
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A i believe its atoms
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Reil [10]

Explanation:

If the density of the object is more than that of water, it will sink. Otherwise it will float. The density of water is 1 g/mL.

Substance 1,

Mass, m = 450 g, Volume, V = 90 mL

Density = mass/volume

So,

d_1=\dfrac{450}{90}\\\\=5\ g/mL

It will sink.

Substance 2,

Mass, m = 35 g, Volume, V = 70 mL

Density = mass/volume

So,

d_2=\dfrac{35}{70}\\\\=0.5\ g/mL

It will float.

Substance 3,

Mass, m = 24 g, Volume, V = 12 mL

Density = mass/volume

So,

d_3=\dfrac{24}{12}\\\\=2\ g/mL

It will sink.

7 0
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