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serious [3.7K]
3 years ago
5

What is the inverse of the function f(x)=2x+1

Mathematics
2 answers:
Lostsunrise [7]3 years ago
7 0

Answer:The inverse of the linear function f(x)=2x+1 is f^(-1) (x) = (1/2)x-1/2

Step-by-step explanation:

liubo4ka [24]3 years ago
4 0
The answer is f^-1(x) =x/2 -1/2
The work is shown below

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Explain how to use what you know about whole number division to check your work when you divide with fractions.
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A fraction is a way to describe a part of a whole. A fraction can be a proper fraction, an improper fraction, or a mixed fraction.

<h3>What is a Fraction?</h3>

A fraction is a way to describe a part of a whole. such as the fraction ¼ can be described as 0.25.

A fraction consists of two whole numbers, a number that is above the fraction line which is the Dividend, while the number that is below the fraction line is known as the denominator and is the divisor. The result or the answer which we get when we solve the fraction is the factor or can be said, it is the quotient of the operation.

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4 0
2 years ago
Evaluate the following double integral: xy dA D where the region D is the triangular region whose vertices are (0, 0), (0, 3), (
natulia [17]

Answer:

I= 84

Step-by-step explanation:

for

I=\int\limits^{}_{} \int\limits^{}_D {x*y}  \, dA =  \int\limits^{}_{} \int\limits^{}_D {x*y}  \, dx*dy

since D is the rectangle such that 0<x<3 , 0<y<3

I=\int\limits^{}_{} \int\limits^{}_D {x*y}  \, dA =  \int\limits^{3}_{0} \int\limits^{3}_{0} {x*y}  \, dx*dy =  \int\limits^{3}_{0} {x}  \, dx\int\limits^{3}_{0} {y}  \, dy  = x^{2} /2*y^{2} /2 =  (3^{2} /2 - 0^{2} /2)* (3^{2} /2 - 0^{2} /2) = 3^{4} /4 = 81/4

4 0
3 years ago
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