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Nuetrik [128]
3 years ago
6

Find derivative of the following problem ?

Mathematics
1 answer:
stepan [7]3 years ago
4 0
Let u = x.lnx, , w= x and t = lnx;  w' =1 ;  t' = 1/x

f(x) = e^(x.lnx) ; f(u) = e^(u); f'(u) = u'.e^(u)

let' find the  derivative u' of u
u = w.t
u'=  w't + t'w;  u' = lnx + x/x = lnx+1

u' = x+1 and f'(u) = ln(x+1).e^(xlnx)

finally the derivative of f(x) =ln(x+1).e^(x.lnx) + 2x
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Find UX and the area of △UVW.
Mkey [24]

Answer:

UX ≈ 4.5

△UVW = 49.5 ft²

Step-by-step explanation:

[] We can assume that UX is the midline of this triangle.

22 ft / 2 = 11 ft

XW and VX = 11 ft

[] Now that we have 2 sides of a right traingle, we can find the third.

a² + 11² = 12²

a² + 121 = 144

a² = 20

a = about 4.5, which is side UX

[] Since we have all three sides of the triangle, we can also solve for the total triangle's area. To solve for the area of a triangle, we do base times height divided by 2

22 * 4.5 = 99

99 / 2 = 49.5 ft²

Have a nice day!

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly.

- Heather

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Answer:

AA

Step-by-step explanation:

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It takes Caroline 1/5 of an hour to walk a mile. Four of Caroline's friends time themselves on their own walk of different lengt
slavikrds [6]

Sorry i can't see the question

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Use the surface integral in​ Stokes' Theorem to calculate the circulation of the field Bold Upper F equals x squared Bold i plus
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Stokes' theorem says the integral of the curl of \vec F over a surface S with boundary C is equal to the integral of \vec F along the boundary. In other words, the flux of the curl of the vector field is equal to the circulation of the field, such that

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with 0\le u\le1 and 0\le v\le2\pi.

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\dfrac{\partial\vec s}{\partial\vec u}\times\dfrac{\partial\vec s}{\partial\vec v}=\dfrac u4\,\vec k

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BartSMP [9]
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