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Nuetrik [128]
3 years ago
6

Find derivative of the following problem ?

Mathematics
1 answer:
stepan [7]3 years ago
4 0
Let u = x.lnx, , w= x and t = lnx;  w' =1 ;  t' = 1/x

f(x) = e^(x.lnx) ; f(u) = e^(u); f'(u) = u'.e^(u)

let' find the  derivative u' of u
u = w.t
u'=  w't + t'w;  u' = lnx + x/x = lnx+1

u' = x+1 and f'(u) = ln(x+1).e^(xlnx)

finally the derivative of f(x) =ln(x+1).e^(x.lnx) + 2x
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mylen [45]

Answer:

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Step-by-step explanation:

3 0
1 year ago
Read 2 more answers
Y=x^2+3x-7 y-5x+8=0 how many solutions are there
motikmotik
X^2+3×-7=5x-8
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Y=1+3-7
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7 0
3 years ago
I need help with this algebra 2 question, please dont answer if you dont know
Illusion [34]

Answer:

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Step-by-step explanation:

4 0
3 years ago
First, rewrite 9/10 and 23/25 so that they have a common denominator.
MAVERICK [17]
The cheap answer is, well, all we do is, grab the denominator of one and multiply the other by it, top and bottom, and grab the denominator of the other, and multiply the first one by that one too, that way, both will have the same denominator, and then you can simply check the numerator to see who's larger, let's do so.

\bf \cfrac{9}{\boxed{10}}\qquad \qquad \cfrac{23}{\boxed{25}}
\\\\\\
\cfrac{9\cdot \boxed{25}}{10\cdot \boxed{25}}\implies \cfrac{225}{250}\qquad \qquad \qquad \cfrac{23\boxed{10}}{25\cdot \boxed{10}}\implies \cfrac{230}{250}\\\\
-------------------------------\\\\
\textit{so, which is larger then?}\qquad \cfrac{225}{250}~or~\cfrac{230}{250}?

surely you can tell.
3 0
3 years ago
Read 2 more answers
Hello All,
Lisa [10]

Answer: (going down the table)

1) 5, 8, 6, 1

2) 2, 6, 10, 2

Step-by-step explanation:

count how many are in that bracket.

EG:

1) the amount of numbers between 5 and 10, including 5

etc

8 0
3 years ago
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