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fomenos
3 years ago
8

Double a number increased by Ten equals twelve express the solution in 3 different ways

Mathematics
1 answer:
Zina [86]3 years ago
7 0
First way: 1 doubled is 1+1, which is 2. 2 increased by 10 equals 12.

Second way: 1 doubled is 1*2, which equals 2. 2 increased by 10 equals 12.

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Express the following relations in the set builder notation. Then, determine whether it is reflexive, symmetric, transitive. Ple
pshichka [43]

Answer:

a)Reflexive, not symmetric, transitive

b)Reflexive, not symmetric, transitive

c)Not reflexive, symmetric, not transitive

d)Reflexive, not symmetric, transitive

Step-by-step explanation:

a)

R=\left \{ (a,b)\epsilon  \mathbb{R} \times \mathbb{R} \mid a \leq b\right \}

The relation R is reflexive for

a\leq a for every real number a

it is not symmetric because 0 is less than 1, but 1 is not less than 0

it is transitive

a\leq and b\leq c\Rightarrow a\leq c

So if aRb and bRc, then aRc

b)  

R=\left \{ (m,n)\epsilon  \mathbb{Z} \times \mathbb{Z} \mid \exists k\in \mathbb{Z} \ni m=kn \right \}

R is reflexive because m=1.m for every integer m

R is not symmetric: 2 is a factor of 4, but 4 is not a factor of 2

R is transitive:  if mRn and nRp if m=kn and n=qp, so m=(kq)p and kq is an integer , so mRp

c)

R=\left \{ (m,n)\epsilon  \mathbb{Z} \times \mathbb{Z} \mid m\neq n\right \}

R is obviously not reflexive because all numbers equals themselves

R is symmetric: if a different to b, then b different to a

R is not transitive: 1R2 and 2R1 (because 1 different to 2), but 1 = 1

d)

R=\left \{ A,B\mid A\subseteq B \right \}

R is reflexive for every set A is a subset of itself

R is not symmetric {1,2} is a subset of {1,2,3} but {1,2,3} is not a subset of {1,2}

R is transitive: if A is subset of B and B is subset of C, then A is subset of C

8 0
3 years ago
Factorise 3y^3-4xy+2y
sineoko [7]

Answer:

3y^3-4xy+2y

y(3y²-4x+2)

5 0
3 years ago
<img src="https://tex.z-dn.net/?f=z%20%3D%203%20%2B%20i%20%5C%5C%20%7Bz%7D%5E%7B5%7D%20%3D%20" id="TexFormula1" title="z = 3 + i
jarptica [38.1K]

Answer:

z^{5} =  - 12 + 316 i

Step-by-step explanation:

Given that -

z = 3 + i

<em>z^{2} = ( 3 + i )^{2}</em>

<em>z^{2} = 9 + i^{2} + 6 i</em>

<em>z^{2} = 9 - 1 + 6 i</em>

z^{2} = 8 + 6 i

<em>z^{3} = z^{2} × z</em>

<em>z^{3} = ( 8 + 6 i ) × ( 3 + i )</em>

<em>z^{3} = 24 + 8 i + 18 i + 6 i²</em>

<em>z^{3} = 24 + 26 i - 6</em>

z^{3} = 18 + 26 i

z^{5} = z^{2} × z^{3}

<em>z^{5} = ( 8 + 6 i ) × ( 18 + 26 i )</em>

<em>z^{5} = 144 + 208 i + 108 i + 156 i²</em>

<em>z^{5} = 144 + 316 i -156</em>

z^{5} =  - 12 + 316 i

6 0
3 years ago
X ÷ 8 = 8<br>a: 16<br>b: 56<br>c: 62<br>d: 64​
Mariulka [41]
The answer is D!

64 divided by 8 is 8!
7 0
3 years ago
Read 2 more answers
2+2<br><br> (lol so easy xD)
den301095 [7]

Answer:

4

Step-by-step explanation:

  • 2 + 2
  • 1 + 1 + 1 + 1
  • 4
5 0
3 years ago
Read 2 more answers
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