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Kisachek [45]
3 years ago
9

Each week, $25.60 is taken out of leo’s earnings for taxes. What percent of Leo’s weekly earnings is taken out for taxes?

Mathematics
1 answer:
Lyrx [107]3 years ago
4 0

Answer:

You need to include his earnings so we can solve the problem....

Step-by-step explanation:


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Write an equation of the line in slope-intercept form, (-3, -1), (-1, 3)
astra-53 [7]

Answer:

Y=2x+5

Step-by-step explanation:

3 - -1

—-—— = 2=m

-1 - -3

5 0
3 years ago
Find equations of the spheres with center(1, −1, 6)that touch the following planes.a) xy-planeb) yz-planec) xz-plane
Misha Larkins [42]

Given :

Center of sphere , C( 1 , -1 , 6 ) .

To Find :

Find equations of the spheres with center (1, −1, 6) that touch the following planes.a) xy-plane b) yz-plane c) xz-plane .

Solution :

a)

Distance of the point from xy-plane is :

d = 6 units .

So , equation of circle with center C and radius 6 units is :

(x-1)^2+(y-(-1))^2+(z-6)^2=6^2\\\\(x-1)^2+(y+1)^2+(z-6)^2=36

b)

Distance of point from yz-plane is :

d = 1 unit .

So , equation of circle with center C and radius 1 units is :

(x-1)^2+(x+1)^2+(z-6)^2=1^2\\\\(x-1)^2+(x+1)^2+(z-6)^2=1

c)

Distance of point from xz-plane is :

d = 1 unit .

So , equation of circle with center C and radius 1 units is :

(x-1)^2+(x+1)^2+(z-6)^2=1^2\\\\(x-1)^2+(x+1)^2+(z-6)^2=1

Hence , this is the required solution .

4 0
3 years ago
80,531 rounded to nearest thousand
Vlad [161]

Answer:

81,000

Step-by-step explanation:

go to whatever place it is asking you to round nearest to the if it is 5 or more you round up 4 or less it stays the same.

Saying for this -" 5 or more raise the score, 4 or less let it rest"

                                       ^round up^                ^stays the same^

4 0
3 years ago
Read 2 more answers
Please help me with this one
Vladimir79 [104]
Is 10 and 15 because they both have a value of .909
8 0
2 years ago
TIMED QUESTION NEED HELP FASTWhat values of b satisfy 3(2b + 3)2 = 36?
egoroff_w [7]

Answer:

\frac{-3+ 2\sqrt{3}}{2}\textrm{ and }\frac{-3- 2\sqrt{3}}{2}

Step-by-step explanation:

3(2b+3)^{2}=36\\\frac{3(2b+3)^{2}}{3}=\frac{36}{3}\\(2b+3)^{2}=12

Taking square root both sides, we get

\sqrt{(2b+3)^{2}}=\pm \sqrt{12}\\2b+3=\pm \sqrt{4\times 3}\\2b+3=\pm 2\sqrt{3}\\2b+3-3=\pm 2\sqrt{3}-3\\2b=-3\pm 2\sqrt{3}\\b=\frac{-3\pm 2\sqrt{3}}{2}\\b=\frac{-3+ 2\sqrt{3}}{2}\textrm{ or }b=\frac{-3- 2\sqrt{3}}{2}

Therefore, the values of b are:

\frac{-3+ 2\sqrt{3}}{2}\textrm{ and }\frac{-3- 2\sqrt{3}}{2}

5 0
3 years ago
Read 2 more answers
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