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snow_tiger [21]
3 years ago
14

BRAINLIEST WILL BE AWARDED PLEASE HELP

Mathematics
2 answers:
Harman [31]3 years ago
6 0
3 is the answer. Both lines meet at 3.

Hope this helps!
o-na [289]3 years ago
5 0
X=3
Just look at where the two lines intercept and see the x value
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The large sphere has a diameter of 20 feet. Which expression represents the volume, in cubic units, of the shaded part of the sp
aleksandr82 [10.1K]

Answer:

it would be (10)- (4)

Step-by-step explanation:

7 0
2 years ago
Complete the division problem by determining the number that should be placed in the box.
Assoli18 [71]
The solution 349 is given, and its number 3, 4 and 9 determine how many times 13 can be subtracted:

The first subtraction is 3x13 (x100) = 3900
The second subtraction is 4x13 (x10) = 520
The third subtraction is 6x13 = 78

So the answer is 520, which is also what you get when you subtract 78 from 598 of course.
6 0
3 years ago
Read 2 more answers
How is the point (2, 9) in the scatterplot described?
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Im not sure but u can search up the name and see online i would help if i could i hope the advise i gave helps just seach up if no one can help im so sorry i wanted to help but idk this stuff yet sorry
7 0
3 years ago
You are working for a company that designs boxes, bottles and other containers. You are currently working on a design for a milk
ra1l [238]

Volume is a measure of the <u>quantity </u>of <em>substance</em> a given <u>object</u> can contain. The required answers are:

1.1  The <u>volume</u> of each <u>milk</u> carton is 360 cm^{3}.

1.2  The area of <em>cardboard</em> required to make a single <u>milk</u> carton is  332.6 cm^{2}.

1.3  Each <u>carton</u> can hold 0.36 liters of <u>milk</u>.

1.4  The <em>cost</em> of filling the 200 <u>cartons</u> is R 86.40.

The <u>volume</u> of a given <u>shape</u> is the amount of <em>substance</em> that it can contain in a 3-dimensional <em>plane</em>. Examples of <u>shapes</u> with volume include cubes, cuboids, spheres, etc.

The <u>area</u> of a given <u>shape</u> is the amount of <em>space</em> that it would cover on a 2-dimensional <em>plane</em>. Examples of <u>shapes</u> to be considered when dealing with the area include triangle, square, rectangle, trapezium, etc.

The box to be considered in the question is a <u>cuboid</u>. So that;

<u>Volume</u> of <u>cuboid</u> = length x width x height

Thus,

1.1 The <u>volume</u> of each <u>milk</u> carton = length x width x height

                                                         = 6 x 6 x 10

                                                        = 360

The <u>volume</u> of each <u>milk</u> carton is 360 cm^{3}.

1.2 The <em>total area</em> of<em> cardboard </em>required to make a single<u> milk</u> carton can be determined as follows:

i. <u>Area</u> of the <u>rectangular</u> surface = length x width

                                                    = 6 x 10

                                                    = 60

Total <u>area</u> of the <u>rectangular</u> surfaces = 4 x 60

                                                     = 240 cm^{2}

ii. <u>Area</u> of the <u>square</u> surface = side x side = s²

                                                   = 6 x 6  

 <u>Area</u> of the <u>square</u> surface = 36 cm^{2}

iii. There are four <em>semicircular</em> <u>surfaces</u>, this implies a total of 2 <u>circles</u>.

<em>Area</em> of a <u>circle</u> = \pi r^{2}

where r is the <u>radius</u> of the <u>circle</u>.

Total <u>area</u> of the <em>semicircular</em> surfaces = 2 \pi r^{2}

                                        = 2 x \frac{22}{7} x (3)^{2}

                                        = 56.57

Total <u>area</u> of the <em>semicircular</em> surfaces = 56.6 cm^{2}

Therefore, total area of  <em>cardboard</em> required = 240 + 36 + 56.6

                                                            = 332.6 cm^{2}

The <u>area</u> of <em>cardboard</em> required to make a single <em>milk carton</em> is  332.6 cm^{2}.

1.3 Since,

  1 cm^{3}  = 0.001 Liter

Then,

360 cm^{3} = x

x = 360 x  0.001

  = 0.36 Liters

Thus each<em> carton</em> can hold 0.36 liters of <u>milk</u>.

1.4 total cartons = 200

<em>Total volume</em> of <u>milk </u>required = 200 x 0.36

                                                 = 72 litres

But, 1 kiloliter costs R1 200. Thus

<em>Total volume</em> in kiloliters = \frac{72}{1000}

                                         = 0.072 kiloliters

The <u>cost</u> of filling the 200 cartons = R1200 x 0.072

                                         = R 86.40

The <u>cost</u> of filling the 200 <u>cartons</u> is R 86.40.

For more clarifications on the volume of a cuboid, visit: brainly.com/question/20463446

#SPJ1

4 0
2 years ago
Model Real Life You and a partner
shutvik [7]

No. Using multiplication and division, you and your partner will not each get the same number of flips because one can flip 23 times, while the other does it 22 times.

<h3>What are mathematical operations?</h3>

The basic mathematical operations include addition, subtraction, multiplication, and division.

These mathematical operations are performed on numbers, variables, equations, and functions to determine numerical results.

In this situation, we first multiply to get the total number of times the 3 bottles can be flipped.

This total is divided by 2 to see if there will not be a remainder.  The result of the division operation is an odd value.

The number of bottles for flipping = 3

The number of times to flip each bottle = 15 times

The total number of times to flip the 3 bottles = 45 times 93 x 15)

The number of those conducting the bottle flipping experiment = 2

The number of times each partner can flip the bottles evenly = 22.5 times (45/2)

Each partner cannot flip the same number of times based on the mathematical operations because 45 is not an even number.

Learn more about mathematical operations at brainly.com/question/20628271

#SPJ1

7 0
1 year ago
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