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AnnZ [28]
3 years ago
11

Which of the following comparisons is correct?-2 24<−4−6< −5

Mathematics
1 answer:
zlopas [31]3 years ago
4 0
<h3>Answer: Choice D)   -6 < -5</h3>

================================================

Explanation:

Let's go through the answer choices

  • A) This is false because -2 is actually larger than -5. Make a number line and you'll see that -2 is to the right of -5. Numbers on the right are larger than numbers on the left.
  • B) This is also false. The value 0 is smaller than 2. A number line might help show this.
  • C) Also false. It should be 4 > -4. Any positive number is always larger than any negative number.
  • D) This is true. On a number line, -6 is to the left of -5, so -6 is smaller than -5. This makes -6 < -5 a true statement.

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-18 + x = -11

Let's add 18 to both sides

x = 7

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Order these number (smallest to largest)<br><br><br> 35.6 0.356 35.63 3.65 356.06 356.6
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Answer: 0.356, 3.65, 35.6, 35.63, 356.06, 356.6

Step-by-step explanation:

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Marcus baked a loaf of banana bread for a party he cut the loaf into equal size pieces at the end of the party there were six pi
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If one third of the loaf was left and there is six pieces left you multiply 3×6=18


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The hemisphere of radius r is made from a stack of very thin plates such that the density varies with height, r = kz, where k is
Papessa [141]

Answer:

M = ¼ k π R⁴

zG = 8/15 R

Step-by-step explanation:

Note: I'm using lower case r as the radius of each plate and upper case R as the radius of the hemisphere.

The mass of each plate is density times volume:

dm = ρ dV

Each plate has a radius r and a thickness dz.  So the volume of each plate is:

dV = π r² dz

Substituting:

dm = ρ π r² dz

We're told that ρ = kz.  Substituting:

dm = kz π r² dz

Next, we need to write the radius r in terms of the height z.  To do that, we need to look at the cross section (see image below).

The height z and the radius r form a right triangle, where the hypotenuse is the radius of the hemisphere R.

Using Pythagorean theorem:

z² + r² = R²

r² = R² − z²

Substituting:

dm = kπ z (R² − z²) dz

We now have the mass of each plate as a function of its height.  To find the total mass, we integrate between z=0 and z=R.

M = ∫ dm

M = ∫₀ᴿ  kπ z (R² − z²) dz

M = kπ ∫₀ᴿ (R² z − z³) dz

M = kπ (½ R² z² − ¼ z⁴) |₀ᴿ

M = kπ (½ R⁴ − ¼ R⁴)

M = ¼ k π R⁴

Next, to find the center of gravity, we use the weighted average:

zG = (∫ z dm) / (∫ dm)

zG = (∫ z dm) / M

We already found M, we just have to evaluate the other integral:

∫ z dm

∫₀ᴿ kπ z² (R² − z²) dz

kπ ∫₀ᴿ (R² z² − z⁴) dz

kπ (⅓ R² z³ − ⅕ z⁵) |₀ᴿ

kπ (⅓ R⁵ − ⅕ R⁵)

²/₁₅ k π R⁵

Plugging in:

zG = (²/₁₅ k π R⁵) / (¼ k π R⁴)

zG = ⁸/₁₅ R

5 0
3 years ago
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