The amount of the 12 grams sample of gold-195m having a half-life of 30.5 s that would remain after 41 s is 4.726 g
<h3>How to determine the number of half-lives </h3>
- Half-life (t½) = 30.5 s
- Time (t) = 41 s
- Number of half-lives (n) =?
n = t / t½
n = 41 / 30.5
n = 82/61
<h3>How to determine the amount remaining </h3>
- Original amount (N₀) = 12 g
- Number of half-lives (n) = 82/61
N = N₀ / 2ⁿ
N = 12 / 2^(82/61)
N = 4.726 g
Learn more about half life:
brainly.com/question/26374513
I don't know if this is quite what you're looking for but I think it is a diagram showing the relation between variable quantities, typically of two variables, each measured along one of a pair of axes at right angles.
Hope this helps!
Answer:
8 ÷ 15 = 0.5333333333333333 or 0.53
Step-by-step explanation:
it looks like its answers two, four, and five.
tell me how you did !
Answer:
Hope this helps :) If it doesn't I can see what I can do
