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madreJ [45]
3 years ago
13

Fill in the blanks: The original organism is called the _____________, and new organisms are called the _____________. Thx so mu

ch!
Chemistry
1 answer:
Sonbull [250]3 years ago
7 0

Answer:

parent and offspring

Explanation:

I think probably what the question is referring to is in the context of biology, the "original organism" is known as the parent. The young that they reproduce are known as the offspring.

The offspring could be formed by the sexual reproduction of two parental organisms, or the asexual reproduction of just one parental organism.

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2. What group is the atom in?<br> 2 or 2A<br> 6<br> 14 <br> 1
Juliette [100K]

Answer:

\Large \boxed{\mathrm{Group \ 4}}

Explanation:

The number of valence electrons tells us the group number of the neutral atom.

The atom has 4 valence electrons.

The atom is in group 4.

5 0
3 years ago
Read 2 more answers
The shape of a molecule is trigonal planar. How many electron domains around the central atom does this molecule most likely hav
soldi70 [24.7K]
I would think that the answer would be three

Because of the prefix tri- in "tigonal"

Tri- means 3, as in tricycle or triangle

So, it would make sense for the answer to be 3
8 0
3 years ago
Read 2 more answers
Which geoigic feature is most likey to from a mid
zvonat [6]

should be ocean ridges im not sure hope this helps tho

6 0
2 years ago
Read 2 more answers
How many milliliters of 0.125 M FeCl3 are needed to react with an excess of Na2S to produce 3.75 g of Fe2S3 if the percent yield
Katyanochek1 [597]

Answer:

0.912 mL

Explanation:

3 Na2S(aq) + 2 FeCl3(aq) → Fe2S3(s) + 6 NaCl(aq)

FeCl3 is the limiting reactant.

Number of moles of iron III sulphide produced= 3.75g/87.92 g/mol = 0.043 moles

Hence actual yield of Iron III sulphide = 0.043 moles

Theoretical yield of Iron III sulphide = actual yield ×100%/ %yield

Theoretical yield of iron III sulphide= 0.043 ×100/75 = 0.057 moles of Iron III sulphide

From the reaction equation,

2moles of iron III chloride produced 1 mole of iron III sulphide

x moles of iron III chloride, will produce 0.057 of iron III sulphide

x= 2× 0.057= 0.114 moles of iron III chloride

But

Volume= number of moles/ concentration

Volume= 0.114/0.125

Volume= 0.912 mL

4 0
3 years ago
The exhaust gas from an automobile contains 3% by volume of carbon monoxide (CO). Express this concentration in mg/m3 at 25oC an
ser-zykov [4K]

Answer:

24540\frac{mg}{m^3}

Explanation:

Hello,

In this case, since the 3% by volume is represented as:

\frac{3L\ CO}{L\ gas}

By using the ideal gas equation we compute the density of CO:

\rho =\frac{MP}{RT} =\frac{28g/mol*1atm}{0.082\frac{atm*L}{mol*K}*298K}= 0.818g/L

Then we apply the conversion factors as follows:

=\frac{3L\ CO}{100L\ gas}*\frac{0.818g\ CO}{1L\ CO} *\frac{1000mg\ CO}{1g\ CO} *\frac{1000L\ gas}{1m^3\ gas} \\\\=24540\frac{mg}{m^3}

Regards.

4 0
3 years ago
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