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melomori [17]
3 years ago
15

Identify the element that will react with chlorine to form a compound with the general formula XCl4

Chemistry
1 answer:
iVinArrow [24]3 years ago
8 0
Xenon will react with chlorine to form xcl4 As is shown in the formula : Cl--Cl--Cl--Cl l X
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What semimetal can form four single covalent bonds.
lesantik [10]

The right answer is Sillicon.

Silicon (Si) is the chemical element of atomic number 14. It is the most abundant element in the earth's crust after oxygen, or 25.7% of its mass, but it is comparatively only present in relatively small quantities in the material constituting the living.

It is a semi-metal, ie it does not meet all the criteria to be defined as being a metal.

It has four free electrons in the last orbit, so it is able to form four covalent bonds. (the carbon can form 4 covalent bonds but it is not a semi-metal)

4 0
3 years ago
What is the density of water if you have 50.0 grams of water and a volume of 50.0 millimeters
Gnom [1K]

Answer:

\boxed {\tt 1.0 \ g/mL}

Explanation:

Density can be found by dividing the mass by the volume.

d=\frac{m}{v}

The mass of the water is 50.0 grams.

The volume of the water is 50.0 milliliters.

m= 50.0\ g \\v=50.0 \ mL

Substitute the values into the formula.

d=\frac{50.0 \ g}{50.0 \ mL}

Divide.

d= 1.0  \ g/mL

The density of the water is 1.0 grams per milliliter. Also, remember that the density of pure water is always 1.0 g/mL or g/cm³

8 0
3 years ago
Which of the following is a liquid someone help!!!!!
Leya [2.2K]

Answer:

juice, C

Explanation:

4 0
3 years ago
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Pls help me with this
liubo4ka [24]

Answer:

silver

5/20

=0.25.................

6 0
2 years ago
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Air trapped in a cylinder fitted with a piston occupies 145 mL at 1.08 atm
pav-90 [236]

Answer: 0.0014 atm

Explanation:

Given that,

Original pressure of air (P1) = 1.08 atm

Original volume of air (T1) = 145mL

[Convert 145mL to liters

If 1000mL = 1l

145mL = 145/1000 = 0.145L]

New volume of air (V2) = 111L

New pressure of air (P2) = ?

Since pressure and volume are given while temperature is held constant, apply the formula for Boyle's law

P1V1 = P2V2

1.08 atm x 0.145L = P2 x 111L

0.1566 atm•L = 111L•P2

Divide both sides by 111L

0.1566 atm•L/111L = 111L•P2/111L

0.0014 atm = P2

Thus, the new pressure of air when the volume is decreased to 111 L is 0.0014 atm

7 0
3 years ago
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