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kipiarov [429]
3 years ago
12

Which statements describe phase changes? Check all that apply. Particles in a liquid need to move more slowly in order to freeze

. Attractive forces overcome the motion of particles when a solid sublimes. Attractive forces between the particles in a liquid are broken when a liquid boils. Particles in gas move fast enough to make more attractive forces when the gas condenses.
Chemistry
2 answers:
Gemiola [76]3 years ago
7 0
The answer is (A) Particles in a liquid need to move more slowly in order to freeze. and (C),<span>Attractive forces between the particles in a liquid are broken when a liquid boils.</span>
Kipish [7]3 years ago
4 0

Answer: Statements (A), and (C) are correct.

Explanation:

The statements that are true are as follows.

  • Particles in a liquid need to move more slowly in order to freeze.

When a liquid freezes the molecules get attracted towards each other. This attraction of particles occurs slowly. Hence, this statement is true.

  • Attractive forces between the particles in a liquid are broken when a liquid boils.

When temperature is raised, the molecules in a liquid gains kinetic energy and start to move quickly in random directions. As a result, liquid state changes to gaseous state. Hence, this statement is true.

If the attractive force between gas molecules have to be increased, they should be moving slower instead because moving faster does not help attracting molecules together.

Hence, the statement particles in gas move fast enough to make more attractive forces when the gas condenses is not true.


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A 40.2 g sample of a metal heated to 99.3°C is placed into a calorimeter containing 120 g of water at 21.8°C. The final temper
aliina [53]

Answer:

B) Iron (c=0.45 J/g°C)

Explanation:

Given that:-

Heat gain by water = Heat lost by metal

Thus,  

m_{water}\times C_{water}\times (T_f-T_i)=-m_{metal}\times C_{metal}\times (T_f-T_i)

Where, negative sign signifies heat loss

Or,  

m_{water}\times C_{water}\times (T_f-T_i)=m_{metal}\times C_{metal}\times (T_i-T_f)

For water:

Mass = 120 g

Initial temperature = 21.8 °C

Final temperature = 24.5 °C

Specific heat of water = 4.184 J/g°C

For metal:

Mass = 40.2 g

Initial temperature = 99.3 °C

Final temperature = 24.5 °C

Specific heat of metal = ?

So,  

120\times 4.184\times (24.5-21.8)=40.2\times C_{metal}\times (99.3-24.5)

40.2C_{metal}\left(99.3-24.5\right)=120\times \:2.7\times \:4.184

40.2C_{metal}\left(99.3-24.5\right)=1355.616

C_{metal}=0.45\ J/g^0C

<u>This value corresponds to iron. Thus answer is B.</u>

3 0
3 years ago
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SCORPION-xisa [38]
Question #1
Potasium hydroxide (known)
 volume used is 25 ml 
Molarity (concentration) = 0.150 M
Moles of KOH used 
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Sulfuric acid (H2SO4) 
volume used = 15.0 ml
unknown concentration
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2KOH (aq)+ H2SO4(aq) = K2SO4(aq) + 2H2O(l) 
Thus, the Mole ratio of KOH to H2SO4 is 2:1
Therefore, moles of H2SO4 used will be;
      0.00375 × 1/2 = 0.001875 moles
Acid (sulfuric acid)  concentration
    0.001875 moles × 1000/15  
        = 0.125 M

Question #2
Hydrogen bromide (acid)
Volume used = 30 ml
Concentration is 0.250 M
Moles of HBr used;
      0.25 × 30/1000
        =  0.0075 moles 
Sodium Hydroxide (base)
Volume used 20 ml 
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The equation for the reaction is 
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The mole ratio of NaOH : HBr   is 1 : 1
Therefore, moles of NaOH used;
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NaOH concentration will be 
       = 0.0075 moles × 1000/20
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