Answer:C: taking the square root of both sides of the equation
this answer was given to you by shanel :))))
<em><u>HAVE A GREAT DAY YOU LOOK GREAT TODAY ;)</u></em>
:):):):):):):):):):):):):):):):):):):):):)
Answer:
x² + (y+3)² = 4²
Step-by-step explanation:
A close look at the diagram reveals that the center of this circle is (0, -3) and that the radius is 4 units.
Starting from the general equation of a circle, (x - h)² + (y - k)² = r²
and substituting the givens (h = 0, k = -3, r = 4), we get:
x² + (y+3)² = 4². This is Answer B.
Answer:
Step-by-step explanation:
The trash can has a cylinder shape, so we have to calculate the volume of a cylinder.
The volume of a cylinder is given by the formula
where
V is the volume
r is the radius of the base
h is the height of the cylinder
In this problem, we have:
h = 24.90 in. is the height of the can
d = 15.50 in. is the diameter of the can, so the radius is half of this value:
Therefore, the volume of the trash can is:
It looks like the given equation is
sin(2x) - sin(2x) cos(2x) = sin(4x)
Recall the double angle identity for sine:
sin(2x) = 2 sin(x) cos(x)
which lets us rewrite the equation as
sin(2x) - sin(2x) cos(2x) = 2 sin(2x) cos(2x)
Move everything over to one side and factorize:
sin(2x) - sin(2x) cos(2x) - 2 sin(2x) cos(2x) = 0
sin(2x) - 3 sin(2x) cos(2x) = 0
sin(2x) (1 - 3 cos(2x)) = 0
Then we have two families of solutions,
sin(2x) = 0 or 1 - 3 cos(2x) = 0
sin(2x) = 0 or cos(2x) = 1/3
[2x = arcsin(0) + 2nπ or 2x = π - arcsin(0) + 2nπ]
… … … or [2x = arccos(1/3) + 2nπ or 2x = -arccos(1/3) + 2nπ]
(where n is any integer)
[2x = 2nπ or 2x = π + 2nπ]
… … … or [2x = arccos(1/3) + 2nπ or 2x = -arccos(1/3) + 2nπ]
[x = nπ or x = π/2 + nπ]
… … … or [x = 1/2 arccos(1/3) + nπ or x = -1/2 arccos(1/3) + nπ]
