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2 years ago

35 – 2.4 ( 7 – 5) Show each step

Mathematics

1 answer:

saveliy_v [14]2 years ago

5 0

Answer:

35 - 2.4(7-5)

= (35/1)-(24/10)(7-5)

= [(35×10)/(1×10)]-(24/10)(2)

= (350/10)-(24/10)(2)

= (350-24)/10(2)

= 326/10(2)

= 32.6(2)

= 65.2

Thank you.

BY GERALD GREAT.

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Answer:

Step-by-step explanation:

First step: Find the slope, Using the Formula y2 - y1 / x2 - x1 =

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3 years ago

During a promotional weekend, a state fair gives a free admission to every 179th person that enters the fair. On Saturday, there

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Answer:

Step-by-step explanation:

Given that,

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Dividing 8,633 by 179 gives 48 as quotient and 41 as remainder. It means on Saturday 48 people entered for free.

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3 years ago

Find the solution set to this inequality: 2x − 3 > _ 2x − 5 2

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3 years ago

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3 years ago

Read 2 more answers

Please see attachment

Dafna11 [192]

Answer:

a) The value of absolute minimum value = - 0.3536

b) which is attained at $x = \frac{1}{\sqrt{2} }$

Step-by-step explanation:

Step(i):-

Given function

$f(x) = \frac{-x}{2x^{2} +1}$ ...(i)

Differentiating equation (i) with respective to 'x'

$f^{l} = \frac{2x^{2} +1(-1) - (-x) (4x)}{(2x^{2}+1)^{2} }$ ...(ii)

$f^{l}(x) = \frac{2x^{2}-1}{(2x^{2}+1)^{2} }$

Equating Zero

$f^{l}(x) = \frac{2x^{2}-1}{(2x^{2}+1)^{2} } = 0$

$\frac{2x^{2}-1}{(2x^{2}+1)^{2} } = 0$

$2 x^{2}-1 = 0$

$2 x^{2} = 1$

$x^{2} = \frac{1}{2}$

$x = \frac{-1}{\sqrt{2} } , x = \frac{1}{\sqrt{2} }$

Step(ii):-

Again Differentiating equation (ii) with respective to 'x'

$f^{ll}(x) = \frac{(2x^{2} +1)^{2} (4x) - 2(2x^{2} +1) (4x)(2x^{2}-1) }{(2x^{2}+1)^{4} }$

put

$x = \frac{1}{\sqrt{2} }$

$f^{ll} (x) > 0$

The absolute minimum value at $x = \frac{1}{\sqrt{2} }$

Step(iii):-

The value of absolute minimum value

$f(x) = \frac{-x}{2x^{2} +1}$

$f(\frac{1}{\sqrt{2} } ) = \frac{-\frac{1}{\sqrt{2} } }{2(\frac{1}{\sqrt{2} } )^{2} +1}$

on calculation we get

The value of absolute minimum value = - 0.3536

Final answer:-

a) The value of absolute minimum value = - 0.3536

b) which is attained at $x = \frac{1}{\sqrt{2} }$

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