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dezoksy [38]
3 years ago
6

What percent of 86 is 50 to the nearest whole percent

Mathematics
1 answer:
seropon [69]3 years ago
5 0

Answer:

58%

Step-by-step explanation:

50/86 is approximately equal to 0.58, and when you convert that into percentage you get 58%

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Let f(x)=4x2+5. The function g(x) is f(x) translated up 4 units. Enter the equation of g(x) in the box.
Zepler [3.9K]
Al you have to do is add 4 to the equation
This gives you g(x)=4x^2+9 which is your answer

6 0
3 years ago
Read 2 more answers
It appears that people who are mildly obese are less active than leaner people. One study looked at the average number of minute
Molodets [167]

Answer:

10.38% probability that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 410 minutes.

99.55% probability that the mean number of minutes of daily activity of the 6 lean people exceeds 410 minutes

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Mildly obese

Normally distributed with mean 375 minutes and standard deviation 68 minutes. So \mu = 375, \sigma = 68

What is the probability (±0.0001) that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 410 minutes?

So n = 6, s = \frac{68}{\sqrt{6}} = 27.76

This probability is 1 subtracted by the pvalue of Z when X = 410.

Z = \frac{X - \mu}{s}

Z = \frac{410 - 375}{27.76}

Z = 1.26

Z = 1.26 has a pvalue of 0.8962.

So there is a 1-0.8962 = 0.1038 = 10.38% probability that the mean number of minutes of daily activity of the 6 mildly obese people exceeds 410 minutes.

Lean

Normally distributed with mean 522 minutes and standard deviation 106 minutes. So \mu = 522, \sigma = 106

What is the probability (±0.0001) that the mean number of minutes of daily activity of the 6 lean people exceeds 410 minutes?

So n = 6, s = \frac{106}{\sqrt{6}} = 43.27

This probability is 1 subtracted by the pvalue of Z when X = 410.

Z = \frac{X - \mu}{s}

Z = \frac{410 - 523}{43.27}

Z = -2.61

Z = -2.61 has a pvalue of 0.0045.

So there is a 1-0.0045 = 0.9955 = 99.55% probability that the mean number of minutes of daily activity of the 6 lean people exceeds 410 minutes

6 0
3 years ago
in 2001 the average yearly wage was 21842 on average people spent £1644 on their family holiday what percentage of the average y
Vinil7 [7]

The percentage of the average yearly wage is 7.53%.

<h3>What are percentages?</h3>

Percentage can be described as a fraction of an amount that is usually expressed as a number out of hundred.

<h3>What is the percentage of the average yearly wage?</h3>

Percent = (amount spent on family holiday / total yearly wage) x 100

(1644 / 21842) x 100 = 7.53%

To learn more about percentages, please check: brainly.com/question/25764815

8 0
2 years ago
There is a bag filled with 4 blue and 5 red marbles. A marble is taken at random from the bag, the colour is noted and then it i
Vera_Pavlovna [14]

Answer:

2/9?

Explanation:

4+5=9

5>4

2x chance

8 0
3 years ago
(4x-25) help quickly pls
Oduvanchick [21]

Answer: 4x-25 is the answer

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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