Answer:1 4/5
Step-by-step explanation:
If tan0=-3/4 and 0 is in quadrant IV, cos20= (33/25, -17/25, 32/25, 7/25, 24/25?) and tan20= (24/7, -24/7, 7/25, -7/25, 13/7, -1
Oksana_A [137]
Answer:
- cos(2θ) = 7/25
- tan(2θ) = -24/7
Step-by-step explanation:
Sometimes, it is easiest to let a calculator do the work. (See below)
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The magnitude of the tangent is less than 1, so the reference angle will be less than 45°. Then double the angle will be less than 90°, so will remain in the 4th quadrant, where the cosine is positive and the tangent is negative.
You can also use the identities ...
cos(2θ) = (1 -tan(θ)²)/(1 +tan(θ)²)
cos(2θ) = (1 -(-3/4)²)/(1 +(-3/4)²) = ((16-9)/16)/((16+9)/16)
cos(2θ) = 7/25
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tan(2θ) = 2tan(θ)/(1 -tan(θ)²) = 2(-3/4)/((16-9/16) = (-6/4)(16/7)
tan(2θ) = -24/7
Answer:
its fifteen fiths
Step-by-step explanation:
The area would be 83.67 cm.
A semicircle is half of a circle. The perimeter of the semicircle would be half of the perimeter (circumference) of the entire circle. The formula for circumference is:
C=πd
Using our information, we have
22.92 = 0.5(3.14)d
22.92 = 1.57d
Divide both sides by 1.57:
22.92/1.57 = 1.57d/1.57
14.6≈d
Since the diameter is 14.6, the radius is 14.6/2 = 7.3.
We use the radius for the area of the semicircle:
A=0.5πr²
=0.5(3.14)(7.3)²
=83.67
Answer:
D, two and one third
Step-by-step explanation:
i used a calculator