This is the concept of algebra, given that the formula for the surface area of the prism is modeled by the expression SA=2s²+4sh , the surface area of the prism when s=3 and h=5 will be found by substituting the values in our expression as follows;
SA=2(3)²+4×3×5
SA=2(9)+60
SA=18+60
SA=78 sq. units
The answer is 78 sq. units
Because your gonna elminate the loners and soon your going to substitute them for numbers
Answer:
The preceding chapter explored implications of research on learning for general issues relevant to the design of effective learning environments. We now move to a more detailed exploration of teaching and learning in three disciplines: history, mathematics, and science. We chose these three areas in order to focus on the similarities and differences of disciplines that use different methods of inquiry and analysis. A major goal of our discussion is to explore the knowledge required to teach effectively in a diversity of disciplines.
Step-by-step explanation:
The preceding chapter explored implications of research on learning for general issues relevant to the design of effective learning environments. We now move to a more detailed exploration of teaching and learning in three disciplines: history, mathematics, and science. We chose these three areas in order to focus on the similarities and differences of disciplines that use different methods of inquiry and analysis. A major goal of our discussion is to explore the knowledge required to teach effectively in a diversity of disciplines.
Answer:
Volume of Cylinder A is pi times the area of the base times the height
π r2 h = (3.1416)(4)(4)(15) = 753.98 ft3
Volume of Cylinder B is likewise pi times the area of the base times the height
π r2 h = (3.1416)(6)(6)(7) = 791.68 ft3
After pumping all of Cyl A into Cyl B
there will remain empty space in B 791.68 – 753.98 = 37.7 ft3
The percentage this empty space is
of the entire volume is 37.7 / 791.68 = 0.0476 which is 4.8% when rounded to the nearest tenth
.
Guest Apr 26, 2020
Step-by-step explanation:
<span>[2×(10+5)]-5
[2*15]-5
30-5
25</span>
