1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Stella [2.4K]
3 years ago
9

Determine whether the given measures can be the lengths of the sides of a triangle. write yes or no. explain. 9.2, 14.5, 17.1

Mathematics
2 answers:
viktelen [127]3 years ago
8 0

Answer with explanation:

If the length of three segments are, 9.2, 14.5 and 17.1 ,it can be sides of triangle if , Sum of two segments is greater than the third segment.

1.→ 9.2 +14.5=23.7 >17.1

2.→ 14.5 +17.1=41.6 > 9.2

3.→17.1 +9.2=26.3 >14.5

As, sum of any two segment is greater than third segment, so the following measurements can be the the lengths of the sides of a triangle.  

Sergio039 [100]3 years ago
3 0
If the triangle has a angle of 90°, you can solved this exercise by applying the Pythagorean Theorem, which is:

 h²=a²+b²
 h=√(a²+b²)

 h: It is the hypotenuse (The opposite side of the right angle and the longest side of the triangle).

 a and b: They are the legs (The sides that form the right angle).

 The result of h=√(a²+b²), should be 17.1 (The longest side given in the problem). So, let's substitute the values of the legs into the Pythagorean equation:

 h=√(a²+b²)
 h=√((9.2)²+(14.5)²)
 h=17.1

 Therefore, the answer is:

 Yes, the given measures can be the lengths of the sides of a triangle.
You might be interested in
Need help with this….
Svetllana [295]

Answer:

omg im still dont no

Step-by-step explanation:

sorry

8 0
2 years ago
Workout the circumstance of this circle give your answer of π and state its units (diametre 14cm)​
kogti [31]

Answer:

C = 14π cm

Step-by-step explanation:

C = πd

or

C = 2πr

Simply use the 1st equation and plug in the diameter to find you answer.

7 0
3 years ago
Help now fast please
Damm [24]

Answer:

3/4 or .75

Step-by-step explanation:

slope = dy/dx

dy = 1 - -2 = 3

dx = 2 - -2 = 4

slope = 3/4

3 0
3 years ago
Read 2 more answers
What could be the base shape of a cylinder?
Len [333]

Answer:

Circle

Step-by-step explanation:

I believe the correct answer is the base shape of a cylinder would be circle. a cylinder is a closed solid that has two parallel (usually circular) bases connected by a curved surface.This is the most common kind, and if someone just says 'cylinder' this is usually what they mean. The bases can however be almost any curved shape, but the most common alternative to a circle is an ellipse. The shape would then be called an 'elliptical cylinder'. The vertical cross-section of a cylinder is a rectangle, and the horizontal cross-section is a circle.

Hope that was helpful.Thank you!!!

7 0
3 years ago
Read 2 more answers
Enter numbers into the table so that the paired values are in a proportional relationship. In each slot, which numbers would go
goldenfox [79]

Answer:

i think y is 1 x = 12

Step-by-step explanation:


6 0
3 years ago
Read 2 more answers
Other questions:
  • Round each mixed number to the nearest whole number. Then, estimate the difference.
    11·1 answer
  • Would 3.24 be an integer?
    14·1 answer
  • My car gets 27 miles per gallon of gas. If I drive 513 miles, how many gallons of gas will I use?
    13·1 answer
  • If you travel 40 miles east and then turn around and drive 12 miles west, the displacement is?
    9·2 answers
  • Does a point have width
    14·1 answer
  • The number has the digits
    11·1 answer
  • Last year the backgammon club had 30 members this year the club has 24 members find the percent of decrease of members
    5·1 answer
  • How do you do Inequalities o-o help meh pleaseeeeeeeeeee
    5·1 answer
  • Brian is buying cans of baked beans for a camping trip. Each can is 15 ounces. If he buys 7 cans, about how many pounds of beans
    11·1 answer
  • 5x + 3y - 15 + x<br><br> PLS HELP ASAP FAST
    11·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!