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3 years ago

Determine whether the given measures can be the lengths of the sides of a triangle. write yes or no. explain. 9.2, 14.5, 17.1

Mathematics

2 answers:

viktelen [127]3 years ago

8 0

Answer with explanation:

If the length of three segments are, 9.2, 14.5 and 17.1 ,it can be sides of triangle if , Sum of two segments is greater than the third segment.

1.→ 9.2 +14.5=23.7 >17.1

2.→ 14.5 +17.1=41.6 > 9.2

3.→17.1 +9.2=26.3 >14.5

As, sum of any two segment is greater than third segment, so the following measurements can be the the lengths of the sides of a triangle.

Sergio039 [100]3 years ago

3 0

If the triangle has a angle of 90°, you can solved this exercise by applying the Pythagorean Theorem, which is:

h²=a²+b²
h=√(a²+b²)

h: It is the hypotenuse (The opposite side of the right angle and the longest side of the triangle).

a and b: They are the legs (The sides that form the right angle).

The result of h=√(a²+b²), should be 17.1 (The longest side given in the problem). So, let's substitute the values of the legs into the Pythagorean equation:

h=√(a²+b²)
h=√((9.2)²+(14.5)²)
h=17.1

Therefore, the answer is:

Yes, the given measures can be the lengths of the sides of a triangle.

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Answer:

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Step-by-step explanation:

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3 years ago

An instructor who taught two sections of Math 161A, the first with 20 students and the second with 30 students, gave a midterm e

uranmaximum [27]

Answer:

The answers are for option (a) 0.2070 (b)0.3798 (c) 0.3938

Step-by-step explanation:

Given:

Here Section 1 students = 20

Section 2 students = 30

Here there are 15 graded exam papers.

(a )Here Pr(10 are from second section) = ²⁰C₅ * ³⁰C₁₀/⁵⁰C₁₅= 0.2070

(b) Here if x is the number of students copies of section 2 out of 15 exam papers.

here the distribution is hyper-geometric one, where N = 50, K = 30 ; n = 15

Then,

Pr( x ≥ 10 ; 15; 30 ; 50) = 0.3798

(c) Here we have to find that at least 10 are from the same section that means if x ≥ 10 (at least 10 from section B) or x ≤ 5 (at least 10 from section 1)

so,

Pr(at least 10 of these are from the same section) = Pr(x ≤ 5 or x ≥ 10 ; 15 ; 30 ; 50) = Pr(x ≤ 5 ; 15 ; 30 ; 50) + Pr(x ≥ 10 ; 15 ; 30 ; 50) = 0.0140 + 0.3798 = 0.3938

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valentinak56 [21]

Answer:

Definitions:

The third quartile, denoted by Q3 , is the median of the upper half of the data set. This means that about 75% of the numbers in the data set lie below Q3 and about 25% lie above Q3;

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First, we verify data in increasing order:

21, 24, 25, 28, 29, 35, 37, 38, 42 ( okay);

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Step-by-step explanation:

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