<u>Solution-</u>
<em>The speed 58 m/s with which the ball was shot is the extra data given, as it is already included in the equation as the co-efficient of t .</em>
The height of the arrow (in meters) after t sec is given by
i.
Height of ball after t=1 sec,
(putting t=1 in the height equation)
Height of ball after t=2 sec,
(putting t=2 in the height equation)
∴ Distance traveled in between
And Time taken
ii.
Height of ball after t=1 sec,
(putting t=1 in the height equation)
Height of ball after t=1.5 sec,
(putting t=1.5 in the height equation)
∴ Distance traveled in between
And Time taken
iii.
Height of ball after t=1 sec,
(putting t=1 in the height equation)
Height of ball after t=1.1 sec,
(putting t=1.1 in the height equation)
∴ Distance traveled in between
And Time taken
iv.
Height of ball after t=1 sec,
(putting t=1 in the height equation)
Height of ball after t=1.01 sec,
(putting t=1.01 in the height equation)
∴ Distance traveled in between
And Time taken