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dem82 [27]
3 years ago
10

Katie cut out a rectangle piece of wrapping paper that was 2 times as long and 3 times as wide as the box that she was wrapping.

The box was 5 inches long and 4 inches wide. The box was 5 inches long and 4 inches wide. What is perimeter of the wrapping paper that Katie cut?
Mathematics
1 answer:
klemol [59]3 years ago
7 0
Wouldn't it be 23 bc you add all the outsides ?
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7. Solve the equation.<br> 6(x - 2) = 36<br> 0-8<br> 04<br> 04<br> 08<br> What one
rusak2 [61]

Answer:

8

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

Step-by-step explanation:

<u>Step 1: Define</u>

6(x - 2) = 36

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Divide 6 on both sides:                     x - 2 = 6
  2. Add 2 on both sides:                         x = 8
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The art club is selling their handmade jewelry to raise money for new paints and brushes. Earrings were sold for $6 a pair and n
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I need help for 12xy-15x+6xy
choli [55]
The answer is 18xy-15x
 
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Read 2 more answers
Women athletes at the a certain university have a long-term graduation rate of 67%. Over the past several years, a random sample
lana [24]

Answer:

z=\frac{0.579 -0.67}{\sqrt{\frac{0.67(1-0.67)}{38}}}=-1.193  

p_v =P(z  

So the p value obtained was a very high value and using the significance level given \alpha=0.1 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can conclude that  the proportion of women athletes graduated is not significantly lower than 0.67 or 67% at 10% of significance

Step-by-step explanation:

Data given and notation

n=38 represent the random sample taken

X=22 represent the number of women athletes graduated

\hat p=\frac{22}{38}=0.579 estimated proportion of women athletes graduated

p_o=0.67 is the value that we want to test

\alpha=0.1 represent the significance level

Confidence=90% or 0.90

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion is lower than 0.67 or no:  

Null hypothesis:p \geq 0.67  

Alternative hypothesis:p < 0.67  

When we conduct a proportion test we need to use the z statisitc, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.579 -0.67}{\sqrt{\frac{0.67(1-0.67)}{38}}}=-1.193  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.1. The next step would be calculate the p value for this test.  

Since is a left tailed test the p value would be:  

p_v =P(z  

So the p value obtained was a very high value and using the significance level given \alpha=0.1 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can conclude that  the proportion of women athletes graduated is not significantly lower than 0.67 or 67% at 10% of significance

3 0
3 years ago
The temperature in the afternoon is -8°F. In the evening, the temperature is 6°F colder than in the afternoon.
Neporo4naja [7]

Answer:

-8-6

-8+6

6-(-8)

Step-by-step explanation:

5 0
3 years ago
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