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Anestetic [448]
2 years ago
8

Ur answer will be marked as brainliest

Mathematics
1 answer:
Mars2501 [29]2 years ago
7 0

Answer:

Hi there!

The correct answer is: 2x^{2} + y^{2} + z^{2}  - 2\sqrt{2} xy - 2\sqrt{2} xz + 2yz

Step-by-step explanation:

First of all I want to clarify I used to the fourth identity to solve this problem.

The fourth identity is: (x+y+z)^{2}  = x^{2}  + y^{2} + z^{2} + 2xy + 2xz + 2yz

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George charged a motorized bicycle on his credit card for $2,000 on June 12. His balance before that purchase on that credit car
Gnesinka [82]
The calculation uses the accumulated daily balance method (ADB).
We assume the statement is based on calendar month (rare!).

George owes $500 from beginning to end of June, so 30 days out of 30.
Interest accrued is 500*0.013*30/30=$6.50.
He also owes $2000 from June 12 to June 30, so 19 days inclusively.
Interest accrued is $2000*.013*(19/30)=16.47
Total interest at the end of the month=$6.50+$16.47=$22.97
3 0
3 years ago
How to find HCF of 16 24 and 36 by long division method​
oee [108]

Answer:

GCF=4

Step-by-step explanation:

16/4=4

24/4=6

36/4=9

7 0
3 years ago
How many passwords of 4 digits are there(a)if none of the digits can be repeated?(b)start with 5 and end in an even digit?
liraira [26]

Answer:

5040,56

Step-by-step explanation:

We have to construct pass words of 4 digits

a) None of the digits can be repeated

We have total digits as 0 to 9.

4 digits can be selected form these 10 in 10P4 ways (since order matters in numbers)

No of passwords = 10P4

= 10(9)(8)(7)\\=5040

b) start with 5 and end in even digit

Here we restrain the choices by putting conditions

I digit is compulsorily 5 and hence only one way

Last digit can be any one of 0,2,4,6,8 hence 5 ways

Once first and last selected remaining 2 digits can be selected from remaining 8 digits in 8P2 ways (order counts here)

=56

3 0
3 years ago
X^2 - 2x = 15 how do I solve this quadratic method?<br>I am stuck on it.... please help<br>​
Anarel [89]

Answer:

(x - 5)(x + 3)

Step-by-step explanation:

to solve x² - 2x = 15, we need to get all the terms on one side so we can solve the quadratic equation using factoring. to do this, we subtract 15 from both sides

x² - 2x = 15

- 15         -15

x² - 2x - 15 = 0

now we can factor. we need 2 numbers that when multiplied together give us -15, and when those 2 numbers are added together we get -2

because we have a -15, we can assume that one number must be negative and the other positive, as a negative times a postive is a negative.

we can use 3 and -5 as factors and test it out. we put x in front because we have an x²

(x - 5)(x + 3) < we can FOIL to check to see if this is correct. its not mandatory to check but when you arent sure of the answer you can FOIL it out

FOIL stands for: First, Outside, Inside, and Last terms

F: (x - 5)(x + 3) = x²

O: (x - 5)(x + 3) = -3x

I: (x - 5)(x + 3) = 5x

L: (x - 5)(x + 3) = -15

x² + 3x - 5x - 15 < subtract 3x from 5x

x² - 2x - 15

this checks out, so our answer is (x - 5)(x + 3)

6 0
2 years ago
Read 2 more answers
X/-10 -4 = 16 what's the compute ?
grin007 [14]

Answer:

x=-200

Step-by-step explanation:

x/-10 -4 = 16

Add 4 to each side

x/-10 -4+4 = 16+4

-x/10 = 20

Multiply each side by -10

-x/10 *-10 =-10*20

x = -200

4 0
3 years ago
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