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coldgirl [10]
3 years ago
7

25 decreased by 1/5 of a number is 18

Mathematics
2 answers:
astra-53 [7]3 years ago
5 0
25 - 1/5x = 18
1/5x = 25 - 18
1/5x = 7
x = 7 : 1/5
x = 7 * 5
x = 35
-----------
lorasvet [3.4K]3 years ago
5 0
The number is 35. 25-1/5*35(7)=18
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A mother decides to teach her son about a letter each day of the week. She will choose a letter from the name of the day. For ex
avanturin [10]

Answer:

Check Explanation

Step-by-step explanation:

The days of the week include

Sunday

Monday

Tuesday

Wednesday

Thursday

Friday

Saturday

a) So, the possible letters to be taught include

A, D, E, F, H, I, M, N, O, R, S, T, U, W, Y

There are indeed 15 possible letters.

These are the letters from which all the days of the week are formed from.

b) There are more than 4 letters that can't be taught using this method.

All the letters that cannot be taught using this method because no day of the week contains them include

B, C, G, J, K, L, P, Q, V, X, Z

c) In Tuesday, there are 7 distinct letters.

So, the sample space consist of 7 letters.

n(sample space) = 7

n(Y) = 1

Probability of picking a Y = (1/7)

The reasoning is simple, picking a Y on a Tuesday is one out of 7 possible outcomes, so, the probability of picking a Y on a Tuesday to teach the kid about = (1/7) = 0.143

Hope this Helps!!!

6 0
3 years ago
In a survey of adults who follow more than one sport, 30% listed football as their favorite sport. You survey 15 adults who foll
maxonik [38]

Answer: 0.5

Step-by-step explanation:

Binomial probability formula :-

P(x)=^nC_x\ p^x(q)^{n-x}, where P(x) is the probability of getting success in x trials , n is the total trials and p is the probability of getting success in each trial.

Given : The probability that the adults follow more than one game = 0.30

Then , q= 1-p = 1-0.30=0.70

The number of adults surveyed : n= 15

Let X be represents the adults who follow more than one sport.

Then , the probability that fewer than 4 of them will say that football is their favorite sport,

P(X\leq4)=P(x=0)+P(x=1)+P(x=2)+P(x=3)+P(x=4)\\\\=^{15}C_{0}\ (0.30)^0(0.70)^{15}+^{15}C_{1}\ (0.30)^1(0.70)^{14}+^{15}C_{2}\ (0.30)^2(0.70)^{13}+^{15}C_{3}\ (0.30)^3(0.70)^{12}+^{15}C_{4}\ (0.30)^4(0.70)^{11}\\\\=(0.30)^0(0.70)^{15}+15(0.30)^1(0.70)^{14}+105(0.30)^2(0.70)^{13}+455(0.30)^3(0.70)^{12}+1365(0.30)^4(0.70)^{11}\\\\=0.515491059227\approx0.5

Hence, the probability rounded to the nearest tenth that fewer than 4 of them will say that football is their favorite sport =0.5

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3 years ago
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