Answer: Yes
Step-by-step explanation:
Imagine you have b = 2.
Plug 2 into the equation 2b + b = 3b
You get: 2(2) + 2 = 3(2)
Which solves to be 6 = 6
As long as the variable is the same, in this case b, and they are to the same power, in this case ^1, you can combine them.
Answer:
x = 6
Step-by-step explanation:
<em>If </em><em>two secants</em><em> are drawn from</em><em> a point outside </em><em>the circle, then the </em><em>product</em><em> of the lengths of</em><em> one secant </em><em>and its</em><em> external segment</em><em> equals the </em><em>product </em><em>of the lengths of</em><em> the other secant </em><em>and its</em><em> external segment</em><em> </em>
Let us solve the question.
∵ There is a circle in the given figure
∵ There are two secants intersected at a point outside the circle
∵ The length of one of them = 8
∵ The length of its external segment = x
∵ The length of the other secant = 4 + 8 = 12
∵ The length of its external segment = 4
→ By using the rule above
∴ 8 × x = 12 × 4
∴ 8x = 48
→ Divide both sides by 8
∴ x = 6
Answer:
x = 
Step-by-step explanation:
Given 2 intersecting chords, then the product of the parts of one chord is equal to the product of the parts of the other chord, that is
18x = 9 × 3 = 27 ( divide both sides by 18 )
x = 
=
Answer:
78.5cm^2
Step-by-step explanation:
Half your diameter to get a radius.
D = 10cm
10 divided by 2 = 5
Pi (3.14)
3.14 x 5^2
3.14 x 25 = 78.5cm^2
