Equation of the parabola: y = ax^2 + bx + c. Find a, b, and c.
x of axis of symmetry:
x
=
−
b
2
a
=
3
-> b = -6a
Writing that the graph passing at point (1, 0) and point (4, -3):
(1) 0 = a + b + c -> c = - a - b = - a + 6a = 5a
(2) -3 = 16a + 4b + c --> -3 = 16a - 24a + 5a = -3a --> a = 1
b = -6a = -6; and c = 5a = 5
y
=
x
2
−
6
x
+
5
Check with x = 1: -> y = 1 - 6 + 5 = 0. OK
Answer:
72
Step-by-step explanation:
8 times 9 is 72
Answer:
Step-by-step explanation:
we know that
In this problem we have
substitute the given value in the formula and solve for F
Answer:
Step-by-step explanation:
xy = 42
x+y = - 2 Substitute into the top equation
y = -2 - x Put in for y
x(-2 - x) = 42 Remove the brackets
-2x - x^2 = 42 Subtract 42 from both sides.
-2x - x^2 - 42 = 0 Put in the more normal order.
-x^2 - 2x - 42 = 0 Multiply by -1
x^2 + 2x + 42 = 0
This cannot be factored. It gives complex roots as it is written. I will give you the answer but I kind of doubt the question is correct.
x1 = - 1 + 6.40i
x2 = -1 - 6.40i
Leave a comment if you have a correction.
