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Mila [183]
3 years ago
12

The combined height of one fir tree and one pine tree is 212121 meters. The height of 444 fir trees stacked on top of each other

is 242424 meters taller than one pine tree. How tall are the types of trees that Logan genetically engineered? Each fir tree is meters tall and each pine tree is meters tall.
Mathematics
1 answer:
Drupady [299]3 years ago
4 0

Answer:

Height of fir tree = 9 meters

height of pine tree= 12 meters

Step-by-step explanation:

The combined height of one fir tree and one pine tree is 21 meters. The height of 4 fir trees stacked on top of each other is 24 meters taller than one pine tree.

Let x be the height of fir tree and y be the height of pine tree

x+y=21

Subtract x from both sides

y=21-x

height of 4 fir trees = pine tree +24

4x=y+24

Substitute 21-x or y in the above equation

4x=21-x+24

Add x on both sides

5x=45

Divide by 5 on both sides

x=9

Now plug in 9 for x and find out y

y=21-x

y=21-9

y=12

Height of fir tree = 9 meters

height of pine tree= 12 meters

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Step-by-step explanation:

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There are 2 x's at 1 1/4 mile so he  took 2  1 1/4 mile hikes

We want to know how many more 1 mile hikes than 1 1/4 mile hikes

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3 years ago
A 23% increase followed by a 17% decrease is what percent change?
AVprozaik [17]
A 2.09% increase.

This is just some simple multiplication. A 23% increase is the same as multiplying by 1.23, and a 17% decrease is like multiplying by 0.83, since 100-17=83. Just multiply 1.23*0.83, which equals 1.0209, or a 2.09% increase.
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3 years ago
A bee flies at 15 ft./s directly into a flower bed from a time the beast stays at the flower bed for 12 minutes and then flies d
Zinaida [17]

A) The equation that we need to solve is:

(12ft/s)*(- d/(15ft/s) + 300s) = d

B) The distance to the hive is d = 2000ft.

<h3 /><h3>What equation can you use to find the distance of the flower bed from the hive?</h3>

We know that the bee's speed is 15 ft/s from the hive to the flower bed.

Then stays 12 minutes at the flower bed.

Then returns to the hive with a speed of 12ft/s.

The total time of the journey is 17 minutes, discounting the 12 minutes that the bee was in the flower bed, the travel only took 5 minutes.

Now, if the distance between the hive and the flower bed is d, t₁ as the time that the bee needs to go from the hive to the flower bed, and t₂ as the time in which the bee goes from the flower bed to the hive, we can write the system of equations:

t₂ + t₁ = 5min

(15ft/s)*t₁ = d

(12ft/s)*t₂ = d

With that system of equations, we can find the value of d, which is what we want to get.

Isolating t₂ in the first equation we get:

t₂ = - t₁ + 5min

Now we can replace that in the third equation:

(15ft/s)*t₁ = d

(12ft/s)*(- t₁ + 5min) = d

In the first equation we can isolate t₁:

t₁ = d/(15ft/s)

And replace that in the remaining equation:

(12ft/s)*(- d/(15ft/s) + 5min) = d

5 min = 5*60s = 300s

(12ft/s)*(- d/(15ft/s) + 300s) = d

This is the equation we need to solve to find the value of d.

-(12/15)*d + 3600ft = d

3600ft = d + (12/15)*d = (1 + 12/15)*d = (27/15)*d

(15/27)*3600ft = d = 2000 ft

We conclude that the distance to the hive is 2000ft.

If you want to learn more about systems of equations:

brainly.com/question/13729904

#SPJ1

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Answer:

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