Question

You want the current amplitude through a inductor with an inductance of 4.30 mH (part of the circuitry for a radio receiver) to be 3.00 mA when a sinusoidal voltage with an amplitude of 12.0 V is applied across the inductor.A) What frequency is required?f = ____________Hz.

Answer 1

Answer:

$f=1480.52 Hz$

Explanation:

For the circuit of the radio knowing the voltage in a inductor is VL and the relation of element is:

$V_L=I*Z_L*w$

Where $I= 300mA$, $Z_L=4.3mH$, $V_L= 12V$ and $w=2\pi *f$

Knowing that the frequency influence in the performance of the inductor so:

$V_L=I*Z_L*2\pi *f$

Solve to f'

$f=\frac{V_L}{I*Z_L*2\pi } =\frac{12v}{300mA*43.mH*2\pi}$

$f=1480.52 Hz$