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lbvjy [14]
3 years ago
11

You want the current amplitude through a inductor with an inductance of 4.30 mH (part of the circuitry for a radio receiver) to

be 3.00 mA when a sinusoidal voltage with an amplitude of 12.0 V is applied across the inductor.A) What frequency is required?f = ____________Hz.
Physics
1 answer:
White raven [17]3 years ago
4 0

Answer:

f=1480.52 Hz

Explanation:

For the circuit of the radio knowing the voltage in a inductor is VL and the relation of element is:

V_L=I*Z_L*w

Where I= 300mA, Z_L=4.3mH, V_L= 12V and w=2\pi *f

Knowing that the frequency influence in the performance of the inductor so:

V_L=I*Z_L*2\pi *f

Solve to f'

f=\frac{V_L}{I*Z_L*2\pi } =\frac{12v}{300mA*43.mH*2\pi}

f=1480.52 Hz

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I put +40 points!!!
Aleonysh [2.5K]

Answer:We can solve this using the Law of Conservation of Momentum. If both marbles are in our system, the initial momentum should equal the final momentum.

The initial momentum can be solved for as so:

*  +  =

(0.06)(0.7) + (0.03)(0) = 0.042 [kg * m/s]

So if the system has an initial momentum of 0.042, it should have the same final momentum.

(0.06)(-0.2) + (0.03)() = 0.042

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Explanation:

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3 years ago
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Rob is a high school student taking both algebra and geometry. Last night he had 27 homework problems combined from the two clas
vovikov84 [41]

Answer:

c is the correct answer

Explanation:

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8 0
3 years ago
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A rock with a mass of 6.1 kg falls 1.5 m. What potential energy does it have before the fall?
denpristay [2]

89.67J

Explanation:

Given parameters:

Mass of rock = 6.1kg

Height of fall = 1.5m

Unknown:

Potential energy = ?

Solution:

The potential energy is the energy at rest or due to the position of a body.

Potential energy is mathematically expressed as;

  Potential energy = mgh

m is the mass of the rock

g is the acceleration due to gravity of the rock

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6 0
3 years ago
Which of the following scenarios would be optimal for obtaining a date from radioactive decay using these isotopes: 87Rb, 147Sm,
REY [17]

Answer:

a) 238U, 40K and 87Rb, b)   235U and to a lesser extent 40K , c)  he 235U,

d) possibility is 14C , e)this period would be ideal for 14C , f) 14C should be used since it is the one with the least average life time, even though the measurements must be very careful

Explanation:

One of the applications of radioactive decay is the dating of different systems.

To do this, the quantity of radioactive material in a meter is determined and with the average life time, the time of the sample is found.

Let's write the half-life times of the given materials

87Rb T ½ = 4.75 1010 years

147Sm T ½ = 1.06 1011 years

235U = 7,038 108 years

238U = 4.47 109 years

40K = 1,248 109 years

14C = 5,568 103 years

we already have the half-life of the different elements given

a) meteors. As these decomposed in the formation of the solar system, their life time is around 3 109 to 5 109 years, so it is necessary to look for elements that have a life time of this order, among the candidates we have 238U, 40K and 87Rb if these elements were at the moment of the formation of these meteors, there must still be rations in them, instead elements 14C already completely adequate

b) rock. The formation period is 4.20-108 years, therefore one of the most promising elements is 235U and to a lesser extent 40K since it is more abundant in rocks. The other elements with higher life times have not decayed and therefore will not give a true value and the 14C is completely decayed

c) volcanic ash. Formation time 6107 years, the only element that has the possibility of having a count is the 235U, the others have a life time so long that they have not decayed and the 14C is complete, unbent

d) scarp of an earthquake formation time 5 101 years, The only one that has any possibility is 14C even when it has declined very little, all the others, you have time to long that has not decayed

e) INCA excavation. The time of this civilization is about 10000 to 500 years (104 to 5 102 years), we see that this period would be ideal for 14C since it has some period of cementation, the others have not decayed

f) Tree in Blepharitis. 14C should be used since it is the one with the least average life time, even though the measurements must be very careful because of a period of disintegration. We have such a long time that they have not decayed

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4 years ago
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