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3 years ago

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You want the current amplitude through a inductor with an inductance of 4.30 mH (part of the circuitry for a radio receiver) to

be 3.00 mA when a sinusoidal voltage with an amplitude of 12.0 V is applied across the inductor.A) What frequency is required?f = ____________Hz.

1 answer:

White raven [17]3 years ago

4 0

Answer:

$f=1480.52 Hz$

Explanation:

For the circuit of the radio knowing the voltage in a inductor is VL and the relation of element is:

$V_L=I*Z_L*w$

Where $I= 300mA$ , $Z_L=4.3mH$ , $V_L= 12V$ and $w=2\pi *f$

Knowing that the frequency influence in the performance of the inductor so:

$V_L=I*Z_L*2\pi *f$

Solve to f'

$f=\frac{V_L}{I*Z_L*2\pi } =\frac{12v}{300mA*43.mH*2\pi}$

$f=1480.52 Hz$

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