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ss7ja [257]
3 years ago
7

Which one of the following is a derived Si unit a. Newton, b. Meter, c. Mole, d. Kiogram​

Physics
2 answers:
Sever21 [200]3 years ago
4 0

I think newton is the answer

Yuri [45]3 years ago
3 0

Answer:

<h2>The right answer is Newton.</h2><h2>Bonus answer : Note;; There is a difference between SI base units & Derived SI unit. </h2>

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What resistance would produce a current of 120A from a 6-volt battery?
andriy [413]
120/6=20 ohms :) would be the ans
6 0
3 years ago
an object near the surface of a planet falls 54m in 3s. what is the acceleration due to gravity on that planet
Harman [31]

Answer:

12s

Explanation:

7 0
3 years ago
a person complete a 100m race in 11s. He accelerates for the first two second and then maintains the velocity till the end. what
hjlf

The maximum velocity reached by the person is determined as 11.1 m/s.

<h3>Area under velocity - time graph</h3>

The area under the velocity time graph is the total displacement of the person.

Total Area = area of triangle formed during first 2 seconds + area of rectangle during the last 8 seconds

100 = ¹/₂(2v) + v(11 - 2)

where;

  • v is the maximum velocity

100 = v + 8v

100 = 9v

v = 100/9

v = 11. 1 m/s

Thus, the maximum velocity reached by the person is determined as 11.1 m/s.

Learn  more about maximum velocity here: brainly.com/question/20595261

#SPJ1

4 0
1 year ago
QuestionDetails:
sleet_krkn [62]

To solve the two parts of this problem, we will begin by considering the expressions given for gravitational potential energy and finally kinetic energy (to find velocity). From the potential energy we will obtain its derivative that is equivalent to the Force of gravitational attraction. We will start considering that all the points on the ring are same distance:

r = \sqrt{x^2+R^2}

Then the potential energy is

U = \frac{-GMm}{\sqrt{x^2+R^2}}

PART A) The force is excepted to be along x-axis.

Therefore we take a derivative of U with respect to x.

F = -\frac{dU}{dx}

F = -\frac{d}{dx}(GMm(\frac{1}{R}-\frac{1}{\sqrt{x^2+R^2}}))

F = \frac{GMmx}{(x^2+R^2)^{3/2}}

This expression is the resultant magnitude of the Force F.

PART B) The magnitude of loss in potential energy as the particle falls to the center

U = GMm(\frac{1}{R}-\frac{1}{\sqrt{x^2+R^2}})

According to conservation of energy,

\frac{1}{2}mv^2 = GMm (\frac{1}{R}-\frac{1}{\sqrt{x^2+R^2}})

\therefore v = \sqrt{2GM(\frac{1}{R}-\frac{1}{x^2+R^2})}

7 0
3 years ago
An athlete runs 40 meters north and 30 meters south
Serggg [28]

Answer:

only ten meters north from starting point

Explanation:

7 0
2 years ago
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