All categories

3 years ago

Which one of the following is a derived Si unit a. Newton, b. Meter, c. Mole, d. Kiogram

Physics

2 answers:

Sever21 [200]3 years ago

4 0

I think newton is the answer

Yuri [45]3 years ago

3 0

Answer:

<h2>The right answer is Newton.</h2><h2>Bonus answer : Note;; There is a difference between SI base units & Derived SI unit. </h2>

You might be interested in

An old millstone, used for grinding grain in a gristmill, is a solid cylindrical wheel that can rotate about its central axle wi

MAXImum [283]

Answer:

The answer is I=70,513kgm^2

Explanation:

Here we will use the rotational mechanics equation T=Ia, where T is the Torque, I is the Moment of Inertia and a is the angular acceleration.

When we speak about Torque it´s basically a Tangencial Force applied over a cylindrical or circular edge. It causes a rotation. In this case, we will have that T=Ft*r, where Ft is the Tangencial Forge and r is the radius

Now we will find the Moment of Inertia this way:

$Ft*r=I*a$ -> $(Ft*r)/(a) = I$

Replacing we get that I is:

$I=(200N*0,33m)/(0,936rad/s^2)$

Then $I=70,513kgm^2$

In case you need to find extra information, keep in mind the Moment of Inertia for a solid cylindrical wheel is:

$I=(1/2)*(m*r^2)$

4 0

2 years ago

Which is the product of cellular respiration? A. ATTP B. light C. oxygen D.sugar

MrMuchimi

The answer to the question is A

7 0

3 years ago

Will give brainlist!! Please help!!

Marrrta [24]

Answer:Electromagnetic Energy Example One

activity: cellphones

type of electromagnetic: radio waves

description: we all use our phones to make phone calls and to send a text!

Electromagnetic Energy Example two

activity: microwave

type of electromagnetic: microwave radiation

description: The microwave radiation is absorbed by water molecules in the food which converts to heat intern heats the food do to high levels of radiation being emitted into the food!

Explanation:

i hope this helps you sorry if it doesn't

5 0

2 years ago

A train whistle is heard at 300 Hz as the train approaches town. The train cuts its speed in half as it nears the station, and t

spin [16.1K]

Answer:

The speed of the train before and after slowing down is 22.12 m/s and 11.06 m/s, respectively.

Explanation:

We can calculate the speed of the train using the Doppler equation:

$f = f_{0}\frac{v + v_{o}}{v - v_{s}}$

Where:

f₀: is the emitted frequency

f: is the frequency heard by the observer

v: is the speed of the sound = 343 m/s

$v_{o}$ : is the speed of the observer = 0 (it is heard in the town)

$v_{s}$ : is the speed of the source =?

The frequency of the train before slowing down is given by:

$f_{b} = f_{0}\frac{v}{v - v_{s_{b}}}$ (1)

Now, the frequency of the train after slowing down is:

$f_{a} = f_{0}\frac{v}{v - v_{s_{a}}}$ (2)

Dividing equation (1) by (2) we have:

$\frac{f_{b}}{f_{a}} = \frac{f_{0}\frac{v}{v - v_{s_{b}}}}{f_{0}\frac{v}{v - v_{s_{a}}}}$

$\frac{f_{b}}{f_{a}} = \frac{v - v_{s_{a}}}{v - v_{s_{b}}}$ (3)

Also, we know that the speed of the train when it is slowing down is half the initial speed so:

$v_{s_{b}} = 2v_{s_{a}}$ (4)

Now, by entering equation (4) into (3) we have:

$\frac{f_{b}}{f_{a}} = \frac{v - v_{s_{a}}}{v - 2v_{s_{a}}}$

$\frac{300 Hz}{290 Hz} = \frac{343 m/s - v_{s_{a}}}{343 m/s - 2v_{s_{a}}}$

By solving the above equation for $v_{s_{a}}$ we can find the speed of the train after slowing down:

$v_{s_{a}} = 11.06 m/s$

Finally, the speed of the train before slowing down is:

$v_{s_{b}} = 11.06 m/s*2 = 22.12 m/s$

Therefore, the speed of the train before and after slowing down is 22.12 m/s and 11.06 m/s, respectively.

I hope it helps you!

7 0

2 years ago

Proyektil dengan massa 10 gram ditembak dari senapan dengan massa 5 kg. Kecepatan proyektil sesaat setelah memotret dari laras a

notka56 [123]

Answer:

-0.4 m/s

Explanation:

According to the law of conservation of momentum, the total momentum of the bullet - rifle system must be conserved.

The total momentum before the shot is zero, since they are both at rest:

$p_i = 0$

While the total momentum after the shot can be written as:

$p_f = mv+MV$

where

m = 10 g = 0.010 kg is the mass of the bullet

M = 5 kg is the mass of the rifle

v = 200 m/s is the velocity of the bullet

V is the recoil velocity of the rifle

Since the total momentum is conserved, we can write:

$p_i = p_f$

$0=mv+MV$

And solving for V, we find the recoil velocity:

$V=-\frac{mv}{M}=-\frac{(0.010)(200)}{5}=-0.4 m/s$

and the negative sign indicates that the velocity is opposite to the bullet.

7 0

2 years ago

Which one of the following is a derived Si unit a. Newton, b. Meter, c. Mole, d. Kiogram​

Which one of the following is a derived Si unit a. Newton, b. Meter, c. Mole, d. Kiogram