Answer:
v = 6t² + t + 2, s = 2t³ + ½ t² + 2t
59 m/s, 64.5 m
Explanation:
a = 12t + 1
v = ∫ a dt
v = 6t² + t + C
At t = 0, v = 2.
2 = 6(0)² + (0) + C
2 = C
Therefore, v = 6t² + t + 2.
s = ∫ v dt
s = 2t³ + ½ t² + 2t + C
At t = 0, s = 0.
0 = 2(0)³ + ½ (0)² + 2(0) + C
0 = C
Therefore, s = 2t³ + ½ t² + 2t.
At t = 3:
v = 6(3)² + (3) + 2 = 59
s = 2(3)³ + ½ (3)² + 2(3) = 64.5
An angle of 60 degrees with the negative y-axis could mean 60 degrees clockwise or counterclockwise, which translates to two possible angles (starting from the positive x-axis and moving counterclockwise) of 210 degrees or 330 degrees.
Then the horizontal component
of a velocity vector
with magnitude
could be one of two expressions:


Answer:
B1 = μ_o•I1/2πr
Explanation:
According to the right hand rule, we can say that the magnetic field at the second wire due to the current being carried in first wire is given by;
B1 = μ_o•I1/2πr
Where;
r is distance that separates the two wires
μ_o is a constant known as permeability of free space
I1 is current in wire 1
law of conservation of mechanical energy
PE1 = Ek2
mgh=1/2mv²
h = 12 sin 60

Arsenic in period 4 group 5.