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Anettt [7]
3 years ago
10

D=(8)(40)+(.5)(9.8)(40^2)​

Physics
1 answer:
mart [117]3 years ago
7 0

Answer:

D=Vi*t+1/2a*t^2

D=(8)(40)+(.5)(9.8)(40^2)​

D=(8)(40)+(.5)(9.8)(1600)

D=(320)+(.5)(9.8)(1600)

D=(320)+(4.9)(1600)

D=(320)+7840

D=8180meters.

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Kim is cutting lengths of ribbon so that each length of ribbon equals 8 inches. How many centimeters does 8 inches equal
Aloiza [94]
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7 0
4 years ago
Do you have to use significant figures in converting temperatures
schepotkina [342]
Not only in converting temperatures I think, we always use significant figures every time we want to make some experimental report using the exact data from our experiment. If that isn't experimental report ( some exercise/questions from your textbook) it's not necessary
4 0
4 years ago
Given this graph plotting velocity versus time, estimate the acceleration of object A at points X and Y respectively.
swat32

Point X lies on a horizontal line. We can intuitively say that the slope of the graph at point X is 0, therefore the acceleration at point X is 0m/s²

Point Y lies on a downward slanting line. To calculate the slope of that line, let's apply this equation:

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m = slope, (x₁, y₁) and (x₂, y₂) correspond to the coordinates of the line's endpoints.

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5 0
3 years ago
Read 2 more answers
. A circular wire loop 40 cm in diameter has 100 Ohm resistance and lies in a horizontal plane. A uniform magnetic field points
sergeinik [125]

Answer:

(a) 6.283 Wb (b) 69.11 Wb (c) I = 0.628 A

Explanation:

Given that,

The diameter of the loop, d = 40 cm

Radius, r = 20 cm

Initial magnetic field, B = 5 mT

Final magnetic field, B' = 55 mT

Initial magnetic flux,

\phi_i=BA\\\\=5\times 10^{-3}\times \pi \times 20^2\\\\=6.283\ Wb

Final magnetic flux,

\phi_f=B'A\\\\=55\times 10^{-3}\times \pi \times 20^2\\\\=69.11\ Wb

Due to change in magnetic field an emf will be generated in the loop. It is given by :

\epsilon=-\dfrac{d\phi}{dt}\\\\=\phi_f-\phi_i\\\\=69.11-6.283\\\\=62.827\ V

Let I be the current in the loop. We can find it using Ohm's law such that,

\epsilon=IR\\\\I=\dfrac{\epsilon}{R}\\\\I=\dfrac{62.827}{100}\\\\=0.628\ A

Hence, this is the required solution.

7 0
3 years ago
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photoshop1234 [79]

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On Earth, an astronaut that is 70kg weights 70kg * 9.8 m/s² = 686N

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So, the astronaut’s weight decreases because the moon’s gravitational acceleration is less than Earth’s.

5 0
4 years ago
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