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2 years ago

D=(8)(40)+(.5)(9.8)(40^2)

Physics

1 answer:

mart [117]2 years ago

7 0

Answer:

D=Vi*t+1/2a*t^2

D=(8)(40)+(.5)(9.8)(40^2)

D=(8)(40)+(.5)(9.8)(1600)

D=(320)+(.5)(9.8)(1600)

D=(320)+(4.9)(1600)

D=(320)+7840

D=8180meters.

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A nonconducting sphere has radius R = 2.81 cm and uniformly distributed charge q = +2.35 fC. Take the electric potential at the

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Answer:

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Explanation:

Given that,

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The electric potential at 1.650 cm is $-1.219\times10^{-4}\ V$ .

(b). We need to calculate the potential at a distance r = R

Using formula of potential difference

$V_{R}=-\dfrac{2.35\times10^{-15}}{8\pi\times8.85\times10^{-12}\times2.81\times10^{-2}}$

$V_{R}=-0.0003759\ V$

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3 years ago

D=(8)(40)+(.5)(9.8)(40^2)​

D=(8)(40)+(.5)(9.8)(40^2)