1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Radda [10]
3 years ago
13

The image shows an earthquake occurring on the ocean floor. Identify the epicenter of the earthquake.

SAT
2 answers:
mylen [45]3 years ago
7 0
Where is the picture
Akimi4 [234]3 years ago
7 0
We need the image in order to answer your question. Sorry!
You might be interested in
Why did my fries fall on the ground?
zaharov [31]

Answer:

Gravity pull them on the ground

Explanation:

3 0
3 years ago
One-year-old sydney cries when his father hands him to an unfamiliar babysitter and leaves the room. Sydney’s reaction is a resu
Elena L [17]

Answer: Baby Rafael cries when his mother leaves him with a new babysitter separation anxiety

Explanation:

hope this helps

5 0
2 years ago
Use series to approximate the definite integral i to within the indicated accuracy. i = 1/2 x3 arctan(x) dx 0 (four decimal plac
Valentin [98]

The expression \int\limits^{1/2}_0 {x^3 \arctan(x)} \, dx  is an illustration of definite integrals

The approximated value of the definite integral is 0.0059

<h3>How to evaluate the definite integral?</h3>

The definite integral is given as:

\int\limits^{1/2}_0 {x^3 \arctan(x)} \, dx

For arctan(x), we have the following series equation:

\arctan(x) = \sum\limits^{\infty}_{n = 0} {(-1)^n \cdot \frac{x^{2n + 1}}{2n + 1}}

Multiply both sides of the equation by x^3.

So, we have:

x^3 * \arctan(x) = \sum\limits^{\infty}_{n = 0} {(-1)^n \cdot \frac{x^{2n + 1}}{2n + 1}}  * x^3

Apply the law of indices

x^3 * \arctan(x) = \sum\limits^{\infty}_{n = 0} {(-1)^n \cdot \frac{x^{2n + 1 + 3}}{2n + 1}}

x^3 * \arctan(x) = \sum\limits^{\infty}_{n = 0} {(-1)^n \cdot \frac{x^{2n + 4}}{2n + 1}}

Evaluate the product

x^3 \arctan(x) = \sum\limits^{\infty}_{n = 0} {(-1)^n \cdot \frac{x^{2n + 4}}{2n + 1}}

Introduce the integral sign to the equation

\int\limits^{1/2}_{0}  x^3 \arctan(x)\ dx =\int\limits^{1/2}_{0} \sum\limits^{\infty}_{n = 0} {(-1)^n \cdot \frac{x^{2n + 4}}{2n + 1}}

Integrate the right hand side

\int\limits^{1/2}_{0}  x^3 \arctan(x)\ dx =[ \sum\limits^{\infty}_{n = 0} {(-1)^n \cdot \frac{x^{2n + 4}}{2n + 1}} ]\limits^{1/2}_{0}

Expand the equation by substituting 1/2 and 0 for x

\int\limits^{1/2}_{0}  x^3 \arctan(x)\ dx =[ \sum\limits^{\infty}_{n = 0} {(-1)^n \cdot \frac{(1/2)^{2n + 4}}{2n + 1}} ] - [ \sum\limits^{\infty}_{n = 0} {(-1)^n \cdot \frac{0^{2n + 4}}{2n + 1}} ]

Evaluate the power

\int\limits^{1/2}_{0}  x^3 \arctan(x)\ dx =[ \sum\limits^{\infty}_{n = 0} {(-1)^n \cdot \frac{(1/2)^{2n + 4}}{2n + 1}} ] - 0

\int\limits^{1/2}_{0}  x^3 \arctan(x)\ dx = \sum\limits^{\infty}_{n = 0} {(-1)^n \cdot \frac{(1/2)^{2n + 4}}{2n + 1}}

The nth term of the series is then represented as:

T_n = \frac{(-1)^n}{2^{2n + 5} * (2n + 4)(2n + 1)}

Solve the series by setting n = 0, 1, 2, 3 ..........

T_0 = \frac{(-1)^0}{2^{2(0) + 5} * (2(0) + 4)(2(0) + 1)} = \frac{1}{2^5 * 4 * 1} = 0.00625

T_1 = \frac{(-1)^1}{2^{2(1) + 5} * (2(1) + 4)(2(1) + 1)} = \frac{-1}{2^7 * 6 * 3} = -0.0003720238

T_2 = \frac{(-1)^2}{2^{2(2) + 5} * (2(2) + 4)(2(2) + 1)} = \frac{1}{2^9 * 8 * 5} = 0.00004340277

T_3 = \frac{(-1)^3}{2^{2(3) + 5} * (2(3) + 4)(2(3) + 1)} = \frac{-1}{2^{11} * 10 * 7} = -0.00000634131

..............

At n = 2, we can see that the value of the series has 4 zeros before the first non-zero digit

This means that we add the terms before n = 2

This means that the value of \int\limits^{1/2}_0 {x^3 \arctan(x)} \, dx to 4 decimal points is

\int\limits^{1/2}_0 {x^3 \arctan(x)} \, dx = 0.00625 - 0.0003720238

Evaluate the difference

\int\limits^{1/2}_0 {x^3 \arctan(x)} \, dx = 0.0058779762

Approximate to four decimal places

\int\limits^{1/2}_0 {x^3 \arctan(x)} \, dx = 0.0059

Hence, the approximated value of the definite integral is 0.0059

Read more about definite integrals at:

brainly.com/question/15127807

5 0
2 years ago
A christian renaissance scientist, considered possibly the greatest scientist of all time, was
Oksanka [162]

The greatest scientist of the Christian Renaissance is regarded as Isaac Newton.

Following the Middle Ages, there was a passionate era of "rebirth" for European culture, the arts, politics, and commerce known as the Renaissance. The Renaissance, which is typically characterized as occurring between the 14th and the 17th centuries, fostered the rediscovery of ancient philosophy, literature, and art. Global discovery opened up new places and civilizations to European trade, and some of the greatest philosophers, writers, politicians, scientists, and artists of human history flourished during this time.

Between the Middle Ages and contemporary civilization, the Renaissance is credited for bridging the gap. In Florence, Italy, a city with a vibrant cultural heritage where affluent residents could afford to assist aspiring artists, the Renaissance first emerged.

To know more about Renaissance here

brainly.com/question/13577111

#SPJ4

6 0
2 years ago
The following data is on
liubo4ka [24]

Answer:

Explanation:

1000 Loading

5 0
3 years ago
Other questions:
  • What's the correct answer
    7·1 answer
  • On a particular road map, 1/2 inch represents 18 miles.
    15·1 answer
  • Part A:
    15·1 answer
  • Why do you think it is necessary for a student to pay back NSFAS loan after completing studies?
    9·1 answer
  • Why did joe cheat<br> its true so don´t comment about my questo=ion being incorrect
    8·2 answers
  • That’s a bit sus… don’t anyone see this
    15·1 answer
  • The ratio of the lengths of the sides of abc is 2:3:4.
    6·1 answer
  • Anyone needs help with their assignments
    7·1 answer
  • If 2. 5 moles of h2o are produced how many moles of hydrogen gas must be used.
    8·1 answer
  • Which of the following statements is true concerning medical or dental student supervision
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!