F(x) = 3x^2+6x-2
= 3(x^2+2x-2/3)
= 3(x^2 +2x + 1 - 1 - 2/3)
= 3((x+1)^2 - 1 - 2/3)
= 3((x+1)^2 -5/3))
= 3(x+1)^2 - 5
So our function is in the form:
f(x) = 3(x+1)^2 - 5
where a = 3, h = -1, k = -5
Answer:
1
Step-by-step explanation:
√4x+1=3
√4x = 3 - 1
√4x = 2
squaring both sides,
(√4x)² = 2²
4x = 4
x = 4/4
x = 1
Answer:
yes it is right no one is mistake
Answer:
12
Step-by-step explanation:
Least common multiple means what is the smallest number that both numbers go into
List the prime factors
4= 2*2
12 = 2*2*3
The factors that are in needed to make both are 2 and 3
We need 2 of the 2's and 1 3
2*2*3 = 12
<h3>
Answer: x = 4</h3>
==================================================
Explanation:
Replace f(x) with 0 and solve for x.
f(x) = 3x-12
0 = 3x-12
3x-12 = 0
3x = 12
x = 12/3
x = 4 is a zero, aka root, of the function
---------------
Check:
f(x) = 3x-12
f(4) = 3(4)-12
f(4) = 12-12
f(4) = 0
The answer is confirmed.
