9514 1404 393
Answer:
x = 10·cos(θ) -4·cot(θ)
Step-by-step explanation:
Apparently, we are to assume that the horizontal lines are parallel to each other.
The relevant trig relations are ...
Sin = Opposite/Hypotenuse
Cos = Adjacent/Hypotenuse
If the junction point in the middle of AB is labeled X, then we have ...
sin(θ) = 4/BX ⇒ BX = 4/sin(θ)
cos(θ) = x/XA ⇒ XA = x/cos(θ)
Then ...
BX +XA = AB = 10
Substituting for BX and XA using the above relations, we get
4/sin(θ) +x/cos(θ) = 10
Solving for x gives ...
x = (10 -4/sin(θ))·cos(θ)
x = 10·cos(θ) -4·cot(θ) . . . . . simplify
_____
We used the identity ...
cot(θ) = cos(θ)/sin(θ)
Answer:
1) 2=27
2) x= -11/2
3) no
Step-by-step explanation:
Answer: One possible equation could be y = -2x^2 - 3.
The equation that is given would be in the shape of an upside down parabola. It would have a maximum (vertex) at (0, -3).
The point (0, -3) would also be the y-intercept of the graph.
You could change the -2 to any other negative number and the equation would work in your problem.
SA=2LW+2WH+2HL
SA=2(8*3)+2(3*5)+2(5*8)
SA=158 cm
Answer: (0, -6)
Explanation:
6x - 6 = -4x - 6
10x = 0
x = 0
y = 6(0) - 6
y = 0 - 6
y = -6