Question

Segment YW is an altitude of triangle XYZ. find the area of the triangle. Z=(5,4), W=(5,-1), Y=(8,-1), X=(5,-3)

Answer 1

The answer is C. Let me know if it's right :)

Answer 2

Answer: C)10.5

Step-by-step explanation:

Using distance formula,

Height of triangle =YW=$\sqrt{(5-8)^2+(-1-(-1))^2}=\sqrt{(-3)^2+(0)^2}=\sqrt{9}=3\ units$

Base of triangle (side opposite to the vertex of triangle from which for altitude is formed)XZ=$\sqrt{(5-5)^2+(4-(-3))^2}=\sqrt{(0)^2+(7)^2}=\sqrt{49}=7\ units$

Thus the area of the triangle=$\frac{1}{2}\times\ base\times\ height$

$=\frac{1}{2}\times3\times7=10.5\ units$

Hence, the area of triangle = 10.5 units