Question

PLEASE Answer asap!!!!

Answer 1

Answer:

x=0

Step-by-step explanation:

The axis of symmetry: $x=\frac{-b}{2a}$ when the equation is $y=ax^2+bx+c$

The given equation is:

$y=x^2-6$

To make the a and b values more easily identifiable, we can rewrite it like this:

$y=1x^2+0-6$

Now, we can tell that a=1 and b=0. Plug these into the equation $x=\frac{-b}{2a}$ :

$x=\frac{-(0)}{2(1)}\\x=0$

Therefore, the equation for the axis of symmetry for the parabola is x=0.

I hope this helps!