Question

Ryker is given the graph of the function y= 1/2x^2 - 4 . He wants to find the zeros of the function but is unable to read them exactly from the graph. find the zero in simplest radicle form

Answer 1

$y = \frac{1}{2x^{2} - 4}$
$0 = \frac{1}{2x^{2} - 4}$
$0(2x^{2} - 4) = (2x - 4)(\frac{1}{2x^{2} - 4})$
$0(2x^{2}) - 0(4) = 1$
$0 - 0 = 1$
$0\neq1$