Combinations = n! / (n - r)! r!

In this case:
n = 4
r = 3
Combinations = 4! /(4-3)! 3! = 24/(1)(6) = 24/6 = 4
Answer:
4 arrangements
Answer:
2 x^2 - 3 x + 6
Step-by-step explanation:
Simplify the following:
-(3 x^2 + 4 x - 17) + 5 x^2 + x - 11
-(3 x^2 + 4 x - 17) = -3 x^2 - 4 x + 17:
-3 x^2 - 4 x + 17 + 5 x^2 + x - 11
Grouping like terms, 5 x^2 - 3 x^2 + x - 4 x - 11 + 17 = (5 x^2 - 3 x^2) + (x - 4 x) + (-11 + 17):
(5 x^2 - 3 x^2) + (x - 4 x) + (-11 + 17)
5 x^2 - 3 x^2 = 2 x^2:
2 x^2 + (x - 4 x) + (-11 + 17)
x - 4 x = -3 x:
2 x^2 + -3 x + (-11 + 17)
17 - 11 = 6:
Answer: 2 x^2 - 3 x + 6
The answer has to 2.26 because 2.26 is bigger than 2.25
❄ Hi there,
let us revise the rounding rules and then, get down to rounding the number.

- If the number you need to round is followed by a number from 0 to 4, you round down.
- If the number you need to round is followed by a number that's 5 or more, you round up.
Now we can start the rounding process.
Reading the problem & the directions, we notice that we need to round to 3 decimal places (3 numbers after the decimal point).
Looking at the fourth number, we notice that it's less than 5.
∴ we need to round down ↡
↬
- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -
❄
3 + [_] ÷ 7 = 9
[_] ÷ 7 = 9 - 3
[_] = 6 x 7
[_] = 42
to check, just put 42 in the empty place and solve