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1 answer:

5 0

The answer is D
$\frac{12 {x}^{6} {y}^{ - 4} {z}^{2} }{3 {x}^{2} {y}^{ - 6} {z}^{3} } \\ = \frac{4 {x}^{4} {y}^{2} }{z}$

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