Question

I'm stuck on this please help!!

Answer 1

The answer is D
$\frac{12 {x}^{6} {y}^{ - 4} {z}^{2} }{3 {x}^{2} {y}^{ - 6} {z}^{3} } \\ = \frac{4 {x}^{4} {y}^{2} }{z}$