5. Sarahi found the distance between two points on a coordinate plane to be √74. Can this answer be simplified? Explain.
1 answer:
Answer:
The answer can't be simplified.
Step-by-step explanation:
In order to answer the question, you have to calculate the prime factors of 74 to see if the expression can be simplified.
If at least one of the prime factors has an exponent bigger or equal than 2 (because the expression has a squareroot), then the expression can be simplified using the properties of exponential numbers and irrational numbers to extract the factor or the factors from the squareroot.
(For example the property )
Calculating the prime factors:
74/2 = 37 but 37 is a prime number so:
37/37 =1
74 = 2 x 37
Therefore, can't be expressed as a simplier number.
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9514 1404 393
Answer:
2∛7
Step-by-step explanation:
Putting the expression in simplest form will factor cubes from under the radical.
The correct question statement is:
A probability experiment is conducted in which the sample space of the experiment is S = {4,5,6,7,8,9,10,11,12,13,14,15}. Let event E={7,8,9,10,11,12,13,14,15}. Assume each outcome is equally likely. List the outcomes in
. Find 
.
Solution:
Part 1:
means compliment of the set E. A compliment of a set can be obtained by finding the difference of the set from the universal set. The universal set is the set which contains all the possible outcomes of the events which is S in this case.
So, compliment of E will be equal to S - E. S - E will result in all those elements of S which are not present in E. So, we can write:
Thus the set compliment of E will contain the elements {4,5,6}.So
= {4,5,6}
Part 2)
means probability that if we select any number from the Sample Space S, it will belong the set E compliment.
= (Number of Elements in 
)/Number of elements in S
Number of elements in set S = n(S) = 12
Number of elements in set = 
=3
So,
A probability experiment is conducted in which the sample space of the experiment is S = {4,5,6,7,8,9,10,11,12,13,14,15}. Let event E={7,8,9,10,11,12,13,14,15}. Assume each outcome is equally likely. List the outcomes in
Solution:
Part 1:
So, compliment of E will be equal to S - E. S - E will result in all those elements of S which are not present in E. So, we can write:
Thus the set compliment of E will contain the elements {4,5,6}.So
Part 2)
Number of elements in set S = n(S) = 12
Number of elements in set
So,