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Marina86 [1]
4 years ago
11

Something with volume takes up _____. a. mass b. space c. gravity d. density

Physics
1 answer:
Anni [7]4 years ago
7 0
B, something with volume takes up space.
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Distance and ___ are really the same quantity. A. length b. direction c. speed d. displacement​
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distance and length are the same quantity

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What would happen to a 100N gravitational force if both masses were doubled and the radius were
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3 years ago
Read 2 more answers
2(a)
Tamiku [17]

Answer:

2a.

a=1.13ms^-2

2b.

S=277m

2c.

V=27.7ms-¹

Explanation:

Initial Velocity (U)=22m/s¹

Final Velocity (V)=43m/s²

Time(t) =18.6s

a. a=V-U/t

a=43-22/18.6

a=1.129

a=1.13m/s²

2b.

S=ut+1/2 at²

s=22(10)+1/2×1.13(10)²

s= 220+0.57(10)²

s= 220+0.57(100)

s= 220+57

s=277m

2c.

V=U+AT

V=22+1.13(5)

V=22+5.65

V=22+5.7

V=27.7m/s¹

6 0
3 years ago
A CD has a mass of 17 g and a radius of 6.0 cm. When inserted into a player, the CD starts from rest and accelerates to an angul
Stells [14]

Answer:

τ =9.41 * 10⁻⁴ N*m

Explanation:

Kinematics of the CD

The CD rotates with constant angular acceleration and its angular acceleration is calculated as follows:

\alpha = \frac{\omega_{f}- \omega_{i}}{t}   Formula (1)

Where:

α : angular acceleration. (rad/s²)

ωf: final angular velocity  (rad/s)

ωi : initial angular velocity  (rad/s)

t = time interval (s)

Data

ωf= 20 rad/s

ωi =0

t = 0.65 s.

Calculating of the angular acceleration of the CD

We replace data in the formula (1)

\alpha = \frac{20 -0}{0.65}

α  = 30.77 rad/s²

Newton's second law  in rotation:

F = ma has the equivalent for rotation:

τ = I * α   Formula  (2)

where:

τ : It is the net torque applied to the body.  (N*m)

I :  it is the moment of inertia of the body with respect to the axis of rotation (kg*m²)

α : It is angular acceleration. (rad/s²)

Calculating of the moment of inertia  of the CD

The moment of inertia of a disk with respect to an axis perpendicular to the plane  and passing through its center is calculated by the following formula:

I = (1/2) M*R² Formula (3)

Data

M= 17 g = 17/1000 kg = 0.017 kg  : CD mass

R= 6.0 cm= 6/100 m = 0.06 m : CD  radius

We replace data in the formula (3) :

I = (1/2) ( 0.017 kg)*(0.06 m)² = 3.06 * 10⁻⁵ kg*m²

Calculating of the  net torque acting on the CD

Data

α  = 30.77 rad/s²

I =  3.06 * 10⁻⁵ kg*m²

We replace data in the formula (2) :

τ = I * α

τ =( 3.06 * 10⁻⁵ kg*m²) * (30.77 rad/s²)

τ =9.41 * 10⁻⁴ N*m

3 0
3 years ago
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