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Thepotemich [5.8K]
2 years ago
8

Bumper car A (281 kg) moving

Physics
1 answer:
solmaris [256]2 years ago
4 0

use consevation of linear momentum

  • m1v1+m2v2=(M1+M2)V3
  • 281(2.82)+209(-1.72)=(209+281)V2
  • 792.42-359.48=490v3
  • 432.9=490v3
  • V3=0.88m/s
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What is the speed of a bobsled whose distance-time graph indicates that it traveled 100 m in 25 s?
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As per the question, the distance travelled by bobsled [s] = 100 m

The time taken by the bobsled to travel that distance [t] = 25 s

We are asked to calculate the speed of the bobsled.

The speed of the bobsled is calculated as -

                                            speed\ =\ \frac{distance}{time}

                                            v\ =\ \frac{s}{t}

                                                   =\frac{100\ m}{25\ s}

                                                   =\ 4\ m/s

Hence, the correct answer to the question is A. 4 m/s.  

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3 years ago
Do objects tend to stay moving because of a force called Interia
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The first law of Newton’s law state an object in motion will stay in motion and an object at rest will stay at rest unless acted upon with an outside force. Other know as the law of inertia so yes it does

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3 years ago
Which type of pollution occurs when small particles of soil are suspended in water?
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The type of pollution when small particles of soil are suspended in the water is called Suspended Matter Pollution.  <span>This type of pollution happens when soil enter the water and do not mix in with the water molecules.</span>
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Read 2 more answers
A car is traveling in uniform circular motion on a section of flat roadway whose radius is . The road is slippery, and the car i
Alona [7]

Answer:

The smallest radius will be four (4) times the initial radius

Explanation:

The car maintains a constant angular speed. According to Newton's Second Law F = m a

1. F_{r}=m*A_{n}

2. A_{n}=\frac{v^2}{R_{p}}

Replacing 2 in 1

3. F_{r}=m*\frac{v^2}{R_{p}}

Where:

Fr= Frictional force

Rp= Initial Radius

An= Centripetal Acceleration

M= Mass

V= Velocity

Also we have that:

4. F_{r}=\mu *W=\mu*m*g

μ= Coefficient of friction between the car and the surface

M= Mass

W= Weight

G= Gravity

r is cleared from equation 3

5. R_{p}=m*\frac{v^2}{F_{r}}

Replacing 4 in 5

6. R_{p}=m*\frac{v^2}{\mu*m*g}

Simplifying

7. R_{p}=\frac{v^2}{\mu*g}

Now we have a new velocity equal to twice the initial velocity, We replace it by 2v in equation 7

8. R_{n}=\frac{(2v)^2}{\mu*g}

Computing

9. R_{n}=\frac{4v^2}{\mu*g}

Replacing 5 in 9

R_{n}=4*R_{p}

8 0
3 years ago
Question is down below need rply fast
My name is Ann [436]

The X and Y components are as follows;

1. X = 35 * cos 57 = 19. 1m/s; Y = 35 * sin 57 = 29.4 m/s

2. X = 12 * -cos 34  = -10 m/s; Y = 12 * -sin 34 = -6.7 m/s

3. X = 8 * -cos 90  = 0 m/s; Y = 12 -sin 90 = -8 m/s

4. X = 20 * cos 75 = 5. 2m/s; Y = 20 * (-sin 75) =  -19.3 m/s

<h3>What are the horizontal and vertical components of the vectors?</h3>

The horizontal and vertical components of the velocities are given as follows:

  • Horizontal component, X = x cos θ
  • Vertical component, Y = y sin θ

1. 35 m/s at  57° from x-axis

X = 35 * cos 57 = 19. 1m/s

Y = 35 * sin 57 = 29.4 m/s

2. 12m/s at 34° S of W

X = 12 * -cos 34  = -10 m/s

Y = 12 * -sin 34 = -6.7 m/s

3. 8 m/s at South

X = 8 * -cos 90  = 0 m/s

Y = 12 -sin 90 = -8 m/s

4. 20 m/s at  275° from x-axis

X = 20 * cos 75 = 5. 2m/s

Y = 20 * (-sin 75) =  -19.3 m/s

In conclusion, the X and Y components are found by taking cosines and sine of the angles.

Learn more about horizontal and vertical components at: brainly.com/question/26446720

#SPJ1

8 0
1 year ago
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