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2 years ago

. If the centripetal and thus frictional force between the tires and the roadbed of a car moving in a circular

1 answer:

7 0

<span>In this particular case, where car is moving through curvature, so it is moving in circular motion, force acting on car is centripetal force which holds car not to fly out. Centripetal force is always pointed in the middle of circle. Here frictional force has role of centripetal force. If frictional force is to weak, car would fly out of curvutare.</span>

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What is kinetic energy and what is net force formula

Over [174]

Answer:

Here's the equation for net force: F = ma. The work done on the plane, which becomes its kinetic energy, equals the following: Net force F equals mass times acceleration. Assume that you're pushing in the same direction that the plane is going; in this case, cos 0 degrees = 1, so.

Explanation:

In physics, the kinetic energy of an object is the energy that it possesses due to its motion. It is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity. Having gained this energy during its acceleration, the body maintains this kinetic energy unless its speed changes

Hope this help also looking it up helps ;)

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3 years ago

Which statement describes the process of subduction? Convection currents pull a plate into the mantle. One plate slides beneath

mixas84 [53]

Answer:

Subduction is the geological process in which one plate moves under another due to gravitational pull. The regions where this process occurs called subduction zones.

A subduction is a tectonic plate which is made up of crust and upper layer of mantle. These two layers are called as lithosphere.

Example: South America, central America and cascade volcanoes. In which the oceanic plate descends beneath a continental plate.

7 0

3 years ago

Read 2 more answers

A rolling ball has an initial velocity of 1.6 meters per second. if the ball has a constant acceleration of 0.33 meters per seco

lukranit [14]

We have:

Initial velocity (u) = 1.6 m/s
Constant acceleration (a) = 0.33 m/s²
Time (t) = 3.6 sec

There are five constant acceleration equations that would help us to find the velocity:

$v=u+at$
$s=ut+ \frac{1}{2}at^2$
$s= \frac{1}{2}(u+v)t$
$v^2=u^2+2as$
$s=vt- \frac{1}{2}at^2$

Since we have $u, a, t$ and we want $v$
We will use the first formula $v=u+at$

$v=1.6+(0.33)(3.6)$
$v= 2.788$ m/s

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2 years ago

An experimental rocket designed to land upright falls freely from a height of 2.59 102 m, starting at rest. At a height of 86.9

aleksandr82 [10.1K]

Answer:

The acceleration required by the rocket in order to have a zero speed on touchdown is 19.96m/s²

The rocket's motion for analysis sake is divided into two phases.

Phase 1: the free fall motion of the rocket from the height 2.59*102m to a height 86.9m

Phase 2: the motion of the rocket due to the acceleration of the rocket also from the height 86.9m to the point of touchdown y = 0m.

Explanation:

The initial velocity of the rocket is 0m/s when it started falling from rest under free fall. g = 9.8m/s² t1 is the time taken for phase 1 and t2 is the time taken for phase2.

The final velocity under free fall becomes the initial velocity for the accelerated motion of the rocket in phase 2 and the final velocity or speed in phase 2 is equal to zero.

The detailed step by step solution to the problems can be found in the attachment below.

Thank you and I hope this solution is helpful to you. Good luck.

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2 years ago

b. Comparing and Contrasting Compare the change in atmospheric pressure with elevation to the change in water pressure with dept

olasank [31]

Answer:

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Explanation:

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4 0

3 years ago