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Anna71 [15]
3 years ago
5

To solve a problem using the equation for keplerâs third law, enrico must convert the average distance of mars from the sun from

meters into astronomical units. how should he make the conversion?
Physics
2 answers:
kupik [55]3 years ago
8 0

Answer:

divide the average distance by 1.5 × 1011

Explanation:

just got it wrong that's right answer e2020

Natali5045456 [20]3 years ago
3 0
1 astronomical unit = 149597870700m
Enrico should divide distance in meters with this number.
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What happen when a.c is passed into the coil of dynamo?<br>​
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The dynamo produces Alternating Current output, so in theory yes, it should work in reverse if Alternating Current is input.

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Suppose your hair grows at the rate 1/31 in. per day. find the rate at which it grows in nanometers per second. because the dist
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Hair grows at rate of 9.20nm/s.
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3 years ago
A 17-mm-wide diffraction grating has rulings of 530 lines per millimeter. White light is incident normally on the grating. What
Sedbober [7]

Answer:

377 nm

Explanation:

Number of lines per meter is, N &=530 \times 1000 \\ &=530000 \text { lines } / \mathrm{m} \end{aligned}

Grating element is, d=\frac{1}{N}

=1.8868 \times 10^{-6} \mathrm{~m}[tex]&#10;Order is, n=5&#10;Condition for maximum intensity is, [tex]d \sin \theta=n \lambda

 \lambda &=\frac{1.8868 \times 10^{-6}}{5(\sin 90)} \\&#10;&=0.377 \times 10^{-6} \mathrm{~m} \\&#10;&=377 \mathrm{~nm}

7 0
3 years ago
Q|C (a) You need a 45-ω resistor, but the stockroom has only 20-ω and 50-ω resistors. How can the desired resistance be achieved
NNADVOKAT [17]
  1. In order to achieve the desired resistance under the given circumstances, we would connect two 50 Ohms resistors in parallel and then connect it in series with the 20 Ohms resistors.
  2. In order to get a 35 Ohms resistance under the given circumstances, we would connect two 50 Ohms resistors in parallel and then connect it in series with two 20 Ohms resistors that are connected in parallel.

<h3>How to achieve the desired resistance under these circumstances?</h3>

In order to achieve the desired resistance under the given circumstances, we would connect two 50 Ohms resistors in parallel and then connect it in series with the 20 Ohms resistors.

Mathematically, the total equivalence resistance of two resistors that are connected in parallel is given by:

1/Rt = 1/R₁ + 1/R₂

1/Rt = 1/50 + 1/50

1/Rt = 2/50

1/Rt = 1/25

Rt = 25 Ohms.

Next, we would connect this 25 Ohms resistor in series with the 20 Ohms resistor:

R₃ = 20 + Rt

R₃ = 20 + 25

R₃ = 45 Ohms.

<h3>Part B.</h3>

In order to get a 35 Ohms resistance under the given circumstances, we would connect two 50 Ohms resistors in parallel and then connect it in series with two 20 Ohms resistors that are connected in parallel.

1/Rt = 1/R₁ + 1/R₂

1/Rt = 1/50 + 1/50

1/Rt = 2/50

1/Rt = 1/25

Rt = 25 Ohms.

1/R't = 1/R₁ + 1/R₂

1/R't = 1/20 + 1/20

1/R't = 2/20

1/R't = 1/10

R't = 10 Ohms.

Next, we would connect the 25 Ohms resistor in series with the 10 Ohms resistor:

R₃ = 10 + Rt

R₃ = 10 + 25

R₃ = 35 Ohms.

Read more on resistors in parallel here: brainly.com/question/15121871

#SPJ4

Complete Question:

You need a 45-ω resistor, but the stockroom has only 20-ω and 50-ω resistors.

(a) How can the desired resistance be achieved under these circumstances?

(b) What can you do if you need a 35-ω resistor?

3 0
2 years ago
A rock is dropped from a bridge what happens to the magnitude of the acceleration
White raven [17]

Answer:

9.81 m/s² constant

Explanation:

Any object which is falling has only the acceleration due to gravity acting on it. The value of acceleration due to gravity is 9.81 m/s² which is constant. This is the case if air resistance is not taken into consideration.

The air resistance is a result of the surface area of the object which is falling. This will slow down the object and the velocity reached is called the terminal velocity.

3 0
3 years ago
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