What is the number in standard form 4.9 x 10 by the 8th power

Which statement is true about figures ABCD and A′B′C′D′? (1 point)

sladkih [1.3K]

Answer:

Step-by-step explanation:

A'B'C'D' is obtained by rotating ABCD 180° counterclockwise about the origin and then reflecting it across the x-axis.

A(2, -2) is mapped to A'(-2, -2)

B(1, -4) is mapped to B'(-1, -4)

C(0, -2) is mapped to C'(0, -2)

D(1, -1) is mapped to D'(-1, -1)

If we rotate counterclockwise 180°, every point (x, y) is mapped to (-x, -y):

A(2, -2) gets mapped to (-2, 2)

B(1, -4) gets mapped to (-1, 4)

C(0, -2) gets mapped to (0, 2)

D(1, -1) gets mapped to (-1, 1)

Reflecting these images across the x-axis will then map (x, y) to (x, -y):

(-2, 2) gets mapped to (-2, -2)

(-1, 4) gets mapped to (-1, -4)

(0, 2) gets mapped to (0, -2)

(-1, 1) gets mapped to (-1, -1)

These new coordinates are the same as A'B'C'D'.

3 0

3 years ago

The following parts refer to the letters: LAMEFIREALARM. Recall that "word" means distinguishable letter arrangements. (a) How m

larisa86 [58]

Answer:

Step-by-step explanation:

The word "LAMEFIREALARM" word consists of

2L , 2M, 2E , 2R , 3A , F and I

no of words with the above letters such that M's are not together

=Total No of words- M's are together

Total no of words $=\frac{13!}{4\times 2!\times 3!}=64,864,800$

When M's are together . considering 2 M's as one

therefore there are $\frac{12!}{3\times 2!\times 3!}=9,979,200$

No of ways $=\frac{13!}{4\times 2!\times 3!}-\frac{12!}{3\times 2!\times 3!}=54,885,600$

(b)No of ways such that M's are separated by at least 2 letters

at least 2 letter means 2 letter, 3 letter ......11 letters

So we have to subtract no of ways where there are 1 letter in between M's from total no of ways where 2 M's are not next to each other

No of ways in which there is 1 letter between 2 M's

This can be done by considering 11 cases

In first case Place first M in Starting Position and 2 M on third place

Second case place First M in 2 nd Position and second M on 4 th place

Similarly For 11th case

Place first M in 11th place and second M on 13th place

Total ways

$=\frac{11\times 11!}{3!\times 2!\times 2!\times 2!}$

So , the total number of arrangements of the letters of the word LAMEFIREALARM where the two M's are separated by atleast two letters is

$=\frac{13!}{4\times 2!\times 3!}-\frac{12!}{3\times 2!\times 3!}-\frac{11\times 11!}{3!\times 2!\times 2!\times 2!}$

$=45738000$

7 0

3 years ago

Finf the exact value of sin A and cos A where a = 9 and b = 10 and <c is a right angle

Katyanochek1 [597]

To solve for the longest side, the hypotenuse, you have to use the pythagorean theorem. It will be 10^2 + 9^2 = c^2. 100 + 81 =c^2.
c^2 = 181 so c = sqrt(181).
to find sin of A do opposite/hypotenuse which gives you 9/sqrt(181)
to find cos of A do adjacent/hypotenuse which gives you 10/sqrt(181)