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WITCHER [35]
3 years ago
15

What is the number in standard form 4.9 x 10 by the 8th power

Mathematics
1 answer:
tatuchka [14]3 years ago
7 0
490,000,000 the answer to the question
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A Survey of 85 company employees shows that the mean length of the Christmas vacation was 4.5 days, with a standard deviation of
GenaCL600 [577]

Answer:

The 95% confidence interval for the population's mean length of vacation, in days, is (4.24, 4.76).

The 92% confidence interval for the population's mean length of vacation, in days, is (4.27, 4.73).

Step-by-step explanation:

We have the standard deviations for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 85 - 1 = 84

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 84 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.95}{2} = 0.975. So we have T = 1.989.

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 1.989\frac{1.2}{\sqrt{85}} = 0.26

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 4.5 - 0.26 = 4.24 days

The upper end of the interval is the sample mean added to M. So it is 4.5 + 0.26 = 4.76 days

The 95% confidence interval for the population's mean length of vacation, in days, is (4.24, 4.76).

92% confidence interval:

Following the sample logic, the critical value is 1.772. So

M = T\frac{s}{\sqrt{n}} = 1.772\frac{1.2}{\sqrt{85}} = 0.23

The lower end of the interval is the sample mean subtracted by M. So it is 4.5 - 0.23 = 4.27 days

The upper end of the interval is the sample mean added to M. So it is 4.5 + 0.23 = 4.73 days

The 92% confidence interval for the population's mean length of vacation, in days, is (4.27, 4.73).

8 0
3 years ago
Can someone explain these two math questions to me?<br><br> −2 + 4 ⋅ 32 − 6<br><br> 5 + 42 ÷ 2(3)
zepelin [54]
The first one would be 120 the second one would be 68
8 0
3 years ago
Read 2 more answers
If a coin has been altered so that the probability of heads coming up is 3/10, then the probability of tails coming up is also 3
soldier1979 [14.2K]
False. In a coin, there are 2 possible out comes i.e. a head and a tail. if p is the probability of one side coming up, then the probability of the other side comin up will be q = 1 - p.

Therefore, if the probability of head coming up is 3/10, the probability of tail coming up will be 1 - 3/10 = 7/10.
8 0
3 years ago
7xy + 8z - 2z + 12xy + 10z
cestrela7 [59]

Answer:

19xy + 16z

Step-by-step explanation:

combine like terms

7xy +1 2xy= 19xy

8z - 2z + 10z = 16z

7 0
3 years ago
The minimum number of rigid transformations required to show that polygon ABCDE is congruent to polygon FGHIJ is 1 2 3 4 . A rot
MaRussiya [10]
I found the corresponding image. Pls. see attachment.

<span>The minimum number of rigid transformations required to show that polygon ABCDE is congruent to polygon FGHIJ is 2 (translation and rotation).

A rotation translation must be used to make the two polygons coincide.

A sequence of transformations of polygon ABCDE such that ABCDE does not coincide with polygon FGHIJ is a translation 2 units down and a 90° counterclockwise rotation about point D </span>

8 0
2 years ago
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