For this problem, assume there are 5 grey females, 4 grey males, 2 white females, and 6 white males. As in the book, the biologi
1 answer:
Answer:
The required probability is 0.04411
Step-by-step explanation:
The number of female grey mice = 5.
The number of males grey mice = 4.
The number of female white mice = 2.
The number of male white mice = 6.
The number of mice = 17.
The probability of first mice be male grey =
The probability of second mice be male grey =
The probability of two mice be male grey = = 0.04411
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Answer: a. 1.981 < μ < 2.18
b. Yes.
Step-by-step explanation:
A. For this sample, we will use t-distribution because we're estimating the standard deviation, i.e., we are calculating the standard deviation, and the sample is small, n = 12.
First, we calculate mean of the sample:
2.08
Now, we estimate standard deviation:
s = 0.1564
For t-score, we need to determine degree of freedom and :
df = 12 - 1
df = 11
= 1 - 0.95
α = 0.05
0.025
Then, t-score is
= 2.201
The interval will be
±
2.08 ±
2.08 ± 0.099
The 95% two-sided CI on the mean is 1.981 < μ < 2.18.
B. We are 95% confident that the true population mean for this clinic is between 1.981 and 2.18. Since the mean number performed by all clinics has been 1.95, and this mean is less than the interval, there is evidence that this particular clinic performs more scans than the overall system average.