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Black_prince [1.1K]
4 years ago
6

For this problem, assume there are 5 grey females, 4 grey males, 2 white females, and 6 white males. As in the book, the biologi

st selects two mice randomly. (1) What is the probability of selecting two males given that both are grey?
Mathematics
1 answer:
Leni [432]4 years ago
3 0

Answer:

The required probability is  0.04411

Step-by-step explanation:

The number of female grey mice = 5.

The number of males grey mice = 4.

The number of female white mice = 2.

The number of male white mice = 6.

The number of mice = 17.

The probability of first mice be male grey = \frac{4}{17}

The probability of second mice be male grey = \frac{3}{16}

The probability of two mice be male grey = \frac{4}{17} *\frac{3}{16}  = 0.04411

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bonufazy [111]

Answer:

c = 6.1

Step-by-step explanation:

Given that: B = 18° , C = 152°,  and b = 4.

The missing side, c, can be determined by applying the sine rule which states that:

\frac{b}{Sin B} = \frac{c}{Sin C}

\frac{4}{Sin 18^{o} } = \frac{c}{Sin 152^{o} }

c = \frac{4* Sin 152^{o} }{Sin 18^{o} }

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7 0
3 years ago
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Can't get my head around this at all any help would be greatly appreciated.​
chubhunter [2.5K]

Answer:

The input is -6, hope this helps :D

Step-by-step explanation:

Represent the machines as expressions:

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Answer:

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