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seropon [69]
3 years ago
13

What is the value of b in the equation below?

Mathematics
1 answer:
grin007 [14]3 years ago
6 0

Answer:

I think it is -10

Step-by-step explanation:

Using a^m*a^n=a^(m+n)

b=(m+n)

In this question,

m= -8 and n= -2

so b= (m+n)=(-8+-2) = -10

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Write an equation to describe the relationship in each table.
GuDViN [60]

Answer:

First table: 2x+1=y

Second table: 3x+2=y

Step-by-step explanation:

It was really just testing it out, checking to see if an equation worked for one row, then try in the next. Its hard to explain, but its really just guess and check ;D

I hope this helps!

4 0
3 years ago
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If x-4(x+2) = -15.5, what is the value of x?
lora16 [44]

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Step-by-step explanation:

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1 year ago
Is 1/2 an irrational number?
Vinvika [58]

Answer:

Yes, 1/2 is a irrational number

Step-by-step explanation:

This is the answer because (Google research):

A number is rational if we can write it as a fraction where the numerator and denominator are both integers. However, numbers like 1/2, 46485928/2628242, and -3/7 are also rational, since they are fractions whose numerator and denominator are integers.

Hope this helps!

4 0
3 years ago
I just need answers to the odd numbered questions.<br> I would appreciate the help<br><br> 35 points
Misha Larkins [42]

Answer:

Step-by-step explanation:

Combine real terms and combine complex terms

1) 3 + 2i + 2 - 5i = 3 +2 + 2i - 5i

                          = 5 + (2-5)i

                          = 5 + (-3)i

                          = 5 - 3i

3) 2 - (1 - 2i) + (4 -5i ) - (1 - 3i)  = 2 -1 + 2i + 4 - 5i - 1 + 3i

           {- is distributed to (1 - 2i) & - is distributed to (1- 3i)}

              = 2 - 1  + 4 + 1 + 2i - 5i + 3i

              = 6 +0i = 6

5) 4 - 3i + 4 + 3i = 4 +4 -3i + 3i

                          = 8

7) (3 - 2i)² + (3 +2i) = 3² - 2*3*2i + (2i)² + 3 + 2i     {(a - b)² = a² - 2ab +b²}

= 9 -12i + 4i² + 3 + 2i

= 9 - 12i + 4*(-1) + 3 + 2i       {i²  = -1}

= 9 +3 - 4 - 12i +2i

= 8 - 10i

9) (a +b)^{4} - (a - b)^{4} = 8ab(a^{2} +b^{2})\\\\\\Here, \ a = 1 \ and \ b = i\\\\\\(1+\sqrt{-1})^{4}-(1-\sqrt{-1})^{4}=(1+\sqrt{i^{2}})^{4}-(1-\sqrt{i^{2}})^{4}\\\\=(1+i)^{4}-(1-i)^{4}\\\\=8*1*i(1^{2}+i^{2})\\\\=8i*(1 -1)\\\\=8i*0\\\\=0

6 0
3 years ago
VODU
garri49 [273]

Answer:

r = ∛(3V/4π)

Step-by-step explanation:

The formula for the volume of a sphere is V = (4/3)πr³.

We want to solve this first for r³ and then for r.

Multiplying both sides of V = (4/3)πr³ by 3 yields an equation without fractions:  3V = 4πr³.

Dividing both sides of this equation by 4π isolates r³:

       3V

r³ = -------

       4π

To find r, take the cube root of both sides of

       3V

r³ = -------

       4π

obtaining r = ∛(3V/4π)

3 0
3 years ago
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