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3 years ago

12

Which best describes how the graph of g(x) = radical 25/9x

1 answer:

Vitek1552 [10]3 years ago

3 0

Answer:

Step-by-step explanation:

g(x) = radical 25/9x would be clearer if written as g(x) = radical (25/9)x. Note that radical (25/9) = (5/3).

The graph of g(x) = radical (25/9)x would have the same shape as that of g(x) = radical x EXCEPT that it would be stretched vertically by a factor of (5/3).

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Tell whether the lines for each pair of equations are parallel, perpendicular, or neither

nevsk [136]

Answer: this will help you with this qustion and others involving graphs desmos . com

Step-by-step explanation:

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3 years ago

You have $20. Suppose you make x dollars in tips tomorrow at work. Which inequality must be true for you to have enough money to

Shkiper50 [21]

Answer:

B) x +20 is greater than or less to 45

Step-by-step explanation:

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4 years ago

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bonufazy [111]

I believe the GCF would be 2n

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3 years ago

Determine the dimensions of a rectangular solid (with a square base) with maximum volume if its surface area is 181.5 square cen

3241004551 [841]

Answer:

The base and height of the solid is 5.5cm

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Step-by-step explanation:

Given

$Surface\ Area = 181.5cm^2$

Required

Determine the dimensions that maximizes the volume

Let the base dimension be x and the height be h

The volume is calculated as:

$Volume =x^2 * h$

$Volume =x^2h$

181.5 =x^2h

The surface area (S) is calculated as this:

$S = 2(x^2 + xh + xh)$

$S = 2(x^2 + 2xh)$

$S = 2x^2 + 4xh$

Substitute 181.5 for S

$181.5 = 2x^2 + 4xh$

Make h the subject:

$4xh = 181.5 - 2x^2$

$h = \frac{181.5 - 2x^2}{4x}$

Substitute $h = \frac{181.5 - 2x^2}{4x}$ in $Volume =x^2h$

$V = x^2(\frac{181.5 - 2x^2}{4x})$

$V = x(\frac{181.5 - 2x^2}{4})$

$V = \frac{1}{4}(x)(181.5 - 2x^2)$

$V = \frac{181.5x}{4} - \frac{2x^3}{4}$

$V = \frac{181.5x}{4} - \frac{x^3}{2}$

To get the maximum, we differentiate V with respect to t and set the differentiation to 0

$dV = \frac{181.5}{4} - \frac{3x^2}{2}$

Set to 0

$0 = \frac{181.5}{4} - \frac{3x^2}{2}$

$\frac{3x^2}{2} = \frac{181.5}{4}$

Multiply through by 4

$4 * \frac{3x^2}{2} = \frac{181.5}{4} * 4$

$2*3x^2 = 181.5$

$6x^2 = 181.5$

$x^2 = \frac{181.5}{6}$

$x^2 = 30.25$

$x = \sqrt{30.25$

$x = 5.5$

Recall that:

$h = \frac{181.5 - 2x^2}{4x}$

$h = \frac{181.5 - 2 * 5.5^2}{4 * 5.5}$

$h = \frac{181.5 - 60.5}{22}$

$h = \frac{121}{22}$

$h = 5.5$

So, we have:

$h = 5.5$

$x = 5.5$

<em>Hence, the base and height of the solid is 5.5cm</em>

7 0

3 years ago

The hypotenuse of a 45°-45°-90° triangle measures 4 cm. What is the length of one leg of the triangle

artcher [175]

The angles of the triangle are given as to have measures of <span>45°-45°-90°. This entails that the triangle is an isosceles triangle where the 2 legs of the triangle are of equal length. We calculate as follows:

c</span>² = a² + b²

c² = 2a²

4² = 2a²

a = 2√2

Hope this answers the question. Have a nice day.

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4 years ago

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