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2 years ago

A $1,000 TR Global bond at 80.5 pays 6% interest. Find the annual yield.

1 answer:

3 0

Hi there

Annual yield=annual interest÷bond cost

Annual interest=1,000×0.06=60

Bond cost=1,000×0.805=805

So
Annual yield=60÷805=0.0745×100
=7.45%

Good luck!

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Solve: 8+ x/2= 1/4 (x-4)-1

alexandr402 [8]

|3x+1|=4 : x=−
5
3 or x=1
Pasos
|3x+1|=4
Aplicar las propiedades de los valores absolutos: Pi |u| = a, a>0 entonces u = a or u = −a
3x+1=−4 or 3x+1=4
Mostrar pasos
3x+1=−4 or 3x+1=4

6 0

2 years ago

Use the laws of logarithms and the values given below to evaluate the logarithmic expression.

Sidana [21]

Answer:

c edge

Step-by-step explanation:

6 0

3 years ago

Danielle’s text messaging plan costs 7$ for the first 700 messages and 30 cents for each additional text message. If she owes 18

Artemon [7]

Answer:

738 messages

Step-by-step explanation:

Use the given information to set up an equation. 7 is constant and 0.3 per message, with a total of 18.40.

0.3x + 7 = 18.4

Now solve for x

0.3x = 11.4

x = 38

She sent 38 messages over the standard 700, meaning she sent a total of 738 messages in the month of October

7 0

2 years ago

A survey claims that a college graduate from Smith College can expect an average starting salary of $ 42,000. Fifteen Smith Coll

jek_recluse [69]

<h2>Answer with explanation:</h2>

Let $\mu$ be the average starting salary ( in dollars).

As per given , we have

$H_0: \mu=42000\\\\ H_a:\mu$

Since $H_a$ is left-tailed , so our test is a left-tailed test.

WE assume that the starting salary follows normal distribution .

Since population standard deviation is unknown and sample size is small so we use t-test.

Test statistic : $t=\dfrac{\overline{x}-\mu}{\dfrac{s}{\sqrt{n}}}$ , where n= sample size , $\overline{x}$ = sample mean , s = sample standard deviation.

Here , n= 15 , $\overline{x}= 40,800$ , s= 225

Then, $t=\dfrac{40800-42000}{\dfrac{2250}{\sqrt{15}}}\approx-2.07$

Degree of freedom = n-1=14

The critical t-value for significance level α = 0.01 and degree of freedom 14 is 2.62.

Decision : Since the absolute calculated t-value (2.07) is less than the critical t-value., so we cannot reject the null hypothesis.

Conclusion : We do not have sufficient evidence at 1 % level of significance to support the claim that the average starting salary of the graduates is significantly less that $42,000.

3 0

2 years ago

Question Progress

Stells [14]

Answer:

d = 3h - 6

Step-by-step explanation:

Given

h = $\frac{d}{3}$ + 2 ( subtract 2 from both sides )

h - 2 = $\frac{d}{3}$ ( multiply both sides by 3 )

3(h - 2) = d , that is

d = 3h - 6

8 0

2 years ago