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m_a_m_a [10]
4 years ago
10

(6x^2-2x-6)(8x^2+7x+8)

Mathematics
1 answer:
Sindrei [870]4 years ago
5 0
(6x^2-2x-6)(8x^2+7x+8) \\ =(6x^2*8 x^{2} )+(6x^2*7x)+(6x^2*8) \\ +((-2x)*8x^2)+((-2x)*7x)+((-2x)*8) \\ +((-6)*8x^2)+((-6)*7x)+((-6)*8) \\ =(48 x^{4} )+(42 x^{3} )+(48 x^{2} ) \\ +(-16 x^{3} )+(-14 x^{2} )+(-16x) \\ +(-48 x^{2} )+(-42x)+(-48) \\ =48 x^{4} +(42-16) x^{3} +(48-14-48) x^{2} +(-16-42)x+(-48) \\ =48 x^{4} +26 x^{3} -14x^{2} -58x-48
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